-2(x^4 - 4r^3) should be the factor
Answer:
Step-by-step explanation:
Suppose, on the contrary, a and b are both odd integers, that is:
m and n being some integers numbers.
This way you have to:
![a^{2}-3b^{2}=(2n+1)^2-3(2m+1)^2=(4n^2+4n+1)-3(4m^2+4m+1)\\\\a^{2}-3b^{2}=4(n^2-3m^2+n-3m)-2=4(n(n+1)-3m(m+1))-2](https://tex.z-dn.net/?f=a%5E%7B2%7D-3b%5E%7B2%7D%3D%282n%2B1%29%5E2-3%282m%2B1%29%5E2%3D%284n%5E2%2B4n%2B1%29-3%284m%5E2%2B4m%2B1%29%5C%5C%5C%5Ca%5E%7B2%7D-3b%5E%7B2%7D%3D4%28n%5E2-3m%5E2%2Bn-3m%29-2%3D4%28n%28n%2B1%29-3m%28m%2B1%29%29-2)
The last expression cannot be divisible by 4 since 2 is not divisible by 4. The previous conclusion leads to a contradiction, which was generated from the assumption that a and b were both odd integers. In conclusion, at least one of the two a and b should be an even integer
Answer:
r= 7k/3
Step-by-step explanation: