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marshall27 [118]
3 years ago
15

How do I solve this problem?​

Mathematics
1 answer:
sammy [17]3 years ago
6 0

Answer:

Step-by-step explanation:

The first 2 pieces of this function agree at pi/4, so we will set them equal to each other and sub in pi/4 for x to solve for k:

ksin(\frac{\pi}{4})+(\frac{\pi}{4})^2=\frac{\pi}{4}+2 and

k(\frac{\sqrt{2} }{2})+\frac{\pi^2}{16}=\frac{\pi}{4}+2 and we'll multiply everything by 16 to get rid of the fractions. Doing that gives us:

8k\sqrt{2}=4\pi+32-\pi^2 and

k=\frac{4\pi+32-\pi^2}{8\sqrt{2} } so

k = 3.067

The next one is a bit tricky if you're not up on your natural log equations.

Again, we set these equal to each other because they meet at the value of e. We sub in e for x and solve for m:

x +2=mlne^x

We'll sub in e for x. ln of e to the x power is equal to x, so

e + 2 = me and

m=\frac{e+2}{e} so

m = 1.736

Hope that helps!

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bulgar [2K]

Answer:

f(-1) = 0 and f(4) = 0

Step-by-step explanation:

look at graph to see what point(s) is/are intersecting the y-axis, then use the y-value of the ordered pair

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Answer:

2

Step-by-step explanation:

the points for g is -4,0 and x is 4,2 so... yea 2

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3 years ago
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Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar
bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\

A. P(x=6)

P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\

B. P(x≥10)

P(x\geq10)=1-P(x

P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\

P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\

P(x\geq10)=1-(0.0008+0.0063+0.0251+0.0641+0.1175+0.1645+0.1828+0.1654+0.1241+0.0781)\\\\P(x\geq10)=1-0.9287=0.0713

C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

E(x)=\mu=n\cdot p=25\cdot 0.25=6.25\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot 0.25\cdot 0.75}=\sqrt{4.69}\approx2.17

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Step-by-step explanation:

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Helen [10]

Answer:

333.67 miles

Step-by-step explanation:

She drives her car 91 mi on 3 gal of gas

That’s 91 mi = 3 gal

How many miles can she drive on 11 gal of gas .

Let the mile she can drive by 11 gal of gas be A

At the same rate ,

91 mi = 3 gall

A mi = 11 gal

Cross multiply

A x 3 = 91 x 11

A x 3 = 1001

Divide both sides by 3

A x 3/3 = 1001/3

A = 333.67 miles

At the same rate she’ll drive 333.67 miles on 11 gal of gas

4 0
3 years ago
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