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Reika [66]
3 years ago
15

A cycler leaves home and rides due south for 65 km. She returns home on the same road. What is the cycler's

Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

It doesn't matter what direction she travels, or how far, or whether she uses the same road in both directions.

If she ends up at the same place she started from, then her displacement for the ride is <em>zero</em>.

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The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of
Damm [24]

Answer:

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

5 0
3 years ago
A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is
Veronika [31]

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

F_c = W-N

m\omega^2r = W-N

Here,

m = Net mass

\omega= Angular velocity

r = Radius

W = Weight

N = Normal Force

m\omega^2r = 174-146

The net mass is equivalent to

F = mg \rightarrow m = \frac{F}{g}

Then,

m = \frac{174lb}{32.17ft/s^2}

Replacing we have then,

(\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb

Solving to find the angular velocity we have,

\omega = 0.309rad/s

Therefore the angular velocity is 0.309rad/s

6 0
3 years ago
A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso
jasenka [17]

Answer:

U(3)=-43J

Explanation:

Potential energy is minus the integral of Fdx.  Doing the integration yields:

U=\int\limits {6.0x+12}\, dx

U=-3x^2-12x+C

U(0)=20J

so

U(0)=-3(0)^2+12(0)+C=20

C=20

Now for x=3.0m

U(3)=-3*(3)^2-12(3)+20

U(3)=-43J

6 0
3 years ago
Why do objects fall?
ipn [44]

Answer:

gravity

Explanation:

the Forest of gravity causes objects to fall toward the center of the Earth.

3 0
3 years ago
Read 2 more answers
What engine thrust is required for a rocket of mass 35 kg to leave the launching pad? 3.5 N. 35 N. 351 N. 3,500 N. 35,000 N.
soldi70 [24.7K]

In order for the object to move upward, it needs an upward force
that's at least equal to its own weight.

Weight = (mass) x (gravity) = (35 kg) x (9.8 m/s²) = 343 N.

The engine thrust has to be more than 343 N.

7 0
3 years ago
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