Answer:
v = 5.88 10⁷ m / s
Explanation:
For this exercise we use the relation
E = m c²
also indicate that all energy is converted into kinetic energy
E = K = ½ (M-2m) v²
where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined
we substitute
m c² = ½ (M-2m) v²
v² = 
let's calculate
v = 
v = 
v = 5.88 10⁷ m / s
Distance is 90km,time 1 hr
distance 2 is 82km,time 5 hrs
average speed=total distance travelled/total time taken.
90+82=172/5+1=6
average speed=28.7km over hour
Each electron provides a charge of -1.602 × 10^-19 coulombs.
If there are 8.51 × 10^-6 extra electrons:
1 electron ____________ -1.602 × 10^-19 coulombs
8.51 × 10^6 electrons___x = -1.602 × 10^-19*8.51 × 10^6/1=-1.32×
10^-12 coulombs
So the extra electrons provide a charge of 1.32× 10^-12
coulombs.
So the net charge is -1.32× 10^-12 coulombs (there are more
electrons besides those extra electrons, but there are also protons, so they
don’t affect the net charge – the other electrons just compensate the charge of
the protons).
