The only graph that accurately depict the given motion is graph D.
The given parameters;
- initial position of the man = 0
- direction of the man's first displacement = backward
- time of first motion, t₁ = 6 seconds
- velocity of this first displacement = v₁
- time without any motion (<em>zero movement</em>) = 6 seconds
- direction of the second displacement = forward
- velocity of second displacement = 2v₁
Let the acceleration of the first displacement = a
Acceleration of the second displacement = 2a
From the given graphs we can eliminate every graph without initial decrease or motion towards the negative direction.
The only options with initial motion towards the negative direction are;
The difference between graph B and D;
- in graph B there is a uniform motion for 6 seconds
- in graph D there is no motion for 6 seconds (<em>this is obvious as the line fall directly on top of the horizontal axis maintaining a value of zero for 6 seconds</em>).
Thus, the only graph that accurately depict the given motion is graph D.
Learn more here: brainly.com/question/21095906
The velocity of the object is zero (the object is at rest)
Explanation:
A position vs time graph represents the motion of an object; in particular:
- The position of the object x(t) is represented on the y-axis
- The time t is represented on the x-axis
For a position-time graph, the slope of the graph is given by
where
is the change in position
is the change in time
However, we see that this is equivalent to the definition of velocity:
Therefore, the slope of a position-time graph is equivalent to the velocity of the object.
And so, a horizontal segment on a position vs time graph means that the object has zero velocity (because the slope is zero).
Learn more about velocity:
brainly.com/question/5248528
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True because my mom said to me this morning that i have to take my breakfast
