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natta225 [31]
2 years ago
6

In a survey at a shoe store, 200 customers were asked whether they have

Mathematics
1 answer:
Ghella [55]2 years ago
6 0

Answer:

option D

Step-by-step explanation:

in a shoe store survey there are 200 customers.

given in the table is that people using basketball shoes, not using basket shoes and then there is also classification of people using running or non running shoes.

We have been asked what percentage of people have basketball shoes.

People having basket ball shoes = 0.23 × 200 + 0.31 ×200

                                                       = 108

percentage of people wearing basket ball shoe = \dfrac{108}{200}\times 100

= 54 %

we can also find it by directly adding the given value and multiplying it by 100

= 0.23+0.31 = 0.54 ×100 = 54%

hence, the correct answer is option D

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Answer:

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Step-by-step explanation:

Use PEMDAS (Parenthesis, exponent, multiplication, devision, addition, subtraction)

So....

7 + 2 .... Simplified ( 10/5 =2)

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Hope this helps!

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g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected
Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

6 0
3 years ago
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