When ice melts, its temperature doesn't change ... ice at 32 degrees becomes water at 32 degrees.
When water boils, its temperature doesn't change ... water at 212 degrees becomes steam at 212 degrees.
The row that says both of these is row-D .
Answer:
The kinetic energy K of the moving charge is K = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd
Explanation:
The potential energy due to two charges q₁ and q₂ at a distance d from each other is given by U = kq₁q₂/r.
Now, for the two charges q₁ = q₂ = Q separated by a distance d, the initial potential energy is U₁ = kQ²/d. The initial kinetic energy of the system K₁ = 0 since there is no motion of the charges initially. When the moving charge is at a distance of r = 3d, the potential energy of the system is U₂ = kQ²/3d and the kinetic energy is K₂.
From the law of conservation of energy, U₁ + K₁ = U₂ + K₂
So, kQ²/d + 0 = kQ²/3d + K
K₂ = kQ²/d - kQ²/3d = 2kQ²/3d
So, the kinetic energy K₂ of the moving charge is K₂ = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd
Answer:
frictonal force due to the surface of irregularities
Answer:
d= 64.7 km
displacement vector
Explanation:
total distance = 40 + 30 = 70 km
during 1st flight
during 2nd flight
the two component of r are:
Geographical Direction ![\theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7Br_y%7D%7Br_x%7D%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Ctheta%20%3D%2040.9%5E%7Bo%7D)
Displacement d
d= 64.7 km
displacement vector
