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melamori03 [73]
3 years ago
9

I NEED HELP ASAP!!!

Physics
1 answer:
eduard3 years ago
4 0

Answer:

3. A

4. C

Explanation:

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HELP ME! One airline limits the size of carry-on luggage to a volume of 40,000 cm^3. A passenger has a carry-on that has an area
EleoNora [17]
You must times the area by the volume, look at it as if the area is just one of 23 layers that makes up the volume.
1960x23=45080
so no it cannot be carried as it is 5080cm^3 over the limit
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3 years ago
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An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os
oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

b)

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

d)

Spring Constant:

As w=\sqrt{k/m}

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

e)

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v²    ( A is amplitude of oscillation)

⇒ v=\sqrt{k A^2/m}

⇒ v= \sqrt{179.2 * 0.27/ 0.628}\

⇒ v= 8.78 m/s

f)

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A   ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

5 0
3 years ago
Charge A is sitting in an electric field you know the following information:________
soldi70 [24.7K]

Answer:

The equation that will relate all the given parameters, in other to calculate the potential energy of charge A is:

∆V = ∆U/q, ∆V is potential at charge A position, q is magnitude of charge A, ∆U will be made the subject of the relation, which is the Potential Energy of charge A. The notation "∆" show, the quantities have both in values and final values, in the electric field.(Change in Electric potential and potential energy, due to the effect of the field)

Explanation:

The potential energy of a charged particle (Charge A) in an electric field depends on the magnitude of the charge(Known as stated in the question). However, the potential energy per unit charge has a unique value at any point in the electric field.

6 0
3 years ago
What are the letters that stand for the elements
dalvyx [7]

They are the element symbols. Too many to list here, look up a periodic table.

8 0
3 years ago
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In the following equations, the distance x is in meters, the time tin seconds. and the velocity v is in meters per second. whata
lyudmila [28]

Answer:

A) c₁ = m, c₂ = m/s

B) c₁ = m/s²

C) c₁ = m/s²

D) c₁ = m/s c₂ = °

E) c₁ = m/s , c₂ = /s

Explanation:

A) x = c₁ + c₂t

⇒m = m + (m/s)s (Only same units can be added)

⇒m = m

So, c₁ = m, c₂ = m/s

B) x = 0.5c₁t²

⇒m = 0.5 (m/s²)s²

⇒m = m

So, c₁ = m/s²

C) v² = 2c₁x

⇒m²/s² = 2 (m/s²)m

⇒m²/s² = m²/s²

So, c₁ = m/s²

D) x = c₁ cos(c₂)t

⇒m = (m/s) cos(°)s

⇒m = m

So, c₁ = m/s c₂ = °

E) v² = 2c₁v-(c₂x)²

⇒m²/s² = 2(m/s)(m/s)-(1/s²)(m²)

⇒m²/s² =m²/s²

So, c₁ = m/s , c₂ = /s

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3 years ago
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