Q1. Option 2: basketball
Q2: Newton's first law is <span>the </span>law<span> of inertia. </span>An object at rest stays at rest and an object in motion stays in motion.
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<span>Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.</span>
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<span>Q4 Second law says acceleration is dependent upon net force and mass of the object.</span>
Q5. Basketball accelerates when a player tries to dunk it with both hands.
<span>Q6. Third law says f<span>or every action, there is an equal and opposite reaction.</span></span>
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<span><span>Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.</span></span>
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Answer:
Explanation:
You can approach an expression for the instantaneous velocity at any point on the path by taking the limit as the time interval gets smaller and smaller. Such a limiting process is called a derivative and the instantaneous velocity can be defined as.#3
For the special case of straight line motion in the x direction, the average velocity takes the form: If the beginning and ending velocities for this motion are known, and the acceleration is constant, the average velocity can also be expressed as For this special case, these expressions give the same result. Example for non-constant acceleration#1
Explanation:
change 0.5 g to kg so 0.005kg then change 100 ml to m so 0.001m so density=mass over volume so from there you can continue
A. Illustrates how a theory becomes a law
Answer:
The final image relative to the converging lens is 34 cm.
Explanation:
Given that,
Focal length of diverging lens = -12.0 cm
Focal length of converging lens = 34.0 cm
Height of object = 2.0 cm
Distance of object = 12 cm
Because object at focal point
We need to calculate the image distance of diverging lens
Using formula of lens
The rays are parallel to the principle axis after passing from the diverging lens.
We need to calculate the image distance of converging lens
Now, object distance is ∞
Using formula of lens
The image distance is 34 cm right to the converging lens.
Hence, The final image relative to the converging lens is 34 cm.
