You must times the area by the volume, look at it as if the area is just one of 23 layers that makes up the volume.
1960x23=45080
so no it cannot be carried as it is 5080cm^3 over the limit
Answer:
T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N
Explanation:
a.)
Period: It is already given in the question "oscillator repeats its motion every 0.372 s".
So T=0.372 s
b)
frequency= f = 1/ T
f = 1/ 0.372
f=2.7 Hz
c).
Angular frequency= w= 2πf
w= 2*π*2.7
w=16.9 rad/s
d)
Spring Constant:
As w=
⇒w²= k/m
⇒k= m*w²
⇒k= 0.628 * 16.9² N/m
⇒k=179.2 N/m
e)
The mass will have maximum speed when it passes through the mean position.
At mean position
Maximum elastic potential energy = Maximum kinetic energy
1/2 k A² = 1/2 m v² ( A is amplitude of oscillation)
⇒ v=
⇒ v=
\
⇒ v= 8.78 m/s
f)
Maximum force will be exerted on the block when it is at maximum distance.
F= k* A ( A is amplitude of oscillation)
F= 179.2 * 0.27 N
F= 48.4 N
Answer:
The equation that will relate all the given parameters, in other to calculate the potential energy of charge A is:
∆V = ∆U/q, ∆V is potential at charge A position, q is magnitude of charge A, ∆U will be made the subject of the relation, which is the Potential Energy of charge A. The notation "∆" show, the quantities have both in values and final values, in the electric field.(Change in Electric potential and potential energy, due to the effect of the field)
Explanation:
The potential energy of a charged particle (Charge A) in an electric field depends on the magnitude of the charge(Known as stated in the question). However, the potential energy per unit charge has a unique value at any point in the electric field.
They are the element symbols. Too many to list here, look up a periodic table.
Answer:
A) c₁ = m, c₂ = m/s
B) c₁ = m/s²
C) c₁ = m/s²
D) c₁ = m/s c₂ = °
E) c₁ = m/s , c₂ = /s
Explanation:
A) x = c₁ + c₂t
⇒m = m + (m/s)s (Only same units can be added)
⇒m = m
So, c₁ = m, c₂ = m/s
B) x = 0.5c₁t²
⇒m = 0.5 (m/s²)s²
⇒m = m
So, c₁ = m/s²
C) v² = 2c₁x
⇒m²/s² = 2 (m/s²)m
⇒m²/s² = m²/s²
So, c₁ = m/s²
D) x = c₁ cos(c₂)t
⇒m = (m/s) cos(°)s
⇒m = m
So, c₁ = m/s c₂ = °
E) v² = 2c₁v-(c₂x)²
⇒m²/s² = 2(m/s)(m/s)-(1/s²)(m²)
⇒m²/s² =m²/s²
So, c₁ = m/s , c₂ = /s