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GarryVolchara [31]
3 years ago
10

Which of the following is a scalar quantity?

Physics
1 answer:
makvit [3.9K]3 years ago
4 0

The only scalar quantity is a. 35 m

Explanation:

In physics, there are two types of quantities:

- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:

Speed

Energy

Distance

Time

- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:

Velocity

Force

Acceleration

Displacement

Let's now analyze each given option, to evaluate if it is a scalar or a vector:

a. 35m  --> it is only a unit (no direction), so it is a scalar

b. 20 m to the right  --> it has a direction, so it is a vector

c. 30 m to the North --> it has a direction, so it is a vector

So, the only correct option is a).

Learn more about scalars and vectors:

brainly.com/question/2678571

brainly.com/question/4945130

#LearnwithBrainly

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A wheel 30 cm in diameter accelerates uniformly from 245 rpm to 380 rpm in 6.1 s . Part A How far will a point on the edge of th
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Answer:

A point on the edge of the wheel will travel 199.563 radians at the given time.

Explanation:

Given;

initial angular velocity of the wheel; \omega _i = 245 \ rev/\min = 245\ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 25.66 \ rad/s

final angular velocity of the wheel;

\omega _f = 380 \ rev/\min = 380 \ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 39.80 \ rad/s

radius of the wheel, d/2 = (30 cm ) / 2 = 15 cm = 0.15 m

time of motion, t = 6.1 s

The angular distance traveled by the edge of the wheel is calculated as;

\theta = (\frac{\omega_f + \omega_i}{2} )t\\\\\theta =  (\frac{39.8 + 25.66}{2} )\times 6.1\\\\\theta = 199.653 \ radian

Therefore, a point on the edge of the wheel will travel 199.563 radians at the given time.

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Answer:

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Explanation:

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