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avanturin [10]
3 years ago
6

A hollow spherical planet is inhabited by people who live inside it, where the gravitational is zero. When a very massive space

ship lands on the planet's surface, the gravitational field inside the planet is:__________.
a) nonzero, directed away from the spaceship
b) still zero
c) nonzero, directed toward the spaceship
Physics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

c) nonzero, directed toward the spaceship

Explanation:

As we know that net gravitational force due to spherical shell inside all its points will always be zero

So if planet is a spherical shell then inside the planet net gravitational force is zero on the people living in it

So when massive spaceship land on the surface of planet then the gravitational force of the spaceship is experienced by the people inside the shell

So here the gravitational force on the people is nonzero and it is towards the spaceship which landed on the surface of planet

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It takes 20 N of force to move a box a distance of 10 m. How much work is done on the box?
PIT_PIT [208]

Answer:

Ans is 200 J

Explanation:

Given:  Force = 20N

            Distance = 10m

Work done  = Force * displacement

                    =  20 * 10

                    =  200 J

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4 years ago
What is the name of this atom? I
Vilka [71]

Answer:

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Explanation:

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3 years ago
Read 2 more answers
What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7
joja [24]

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

5 0
4 years ago
Question 2
Nostrana [21]

Answer:

in pretty sure the last one

8 0
4 years ago
Please need help fast
iVinArrow [24]

(a) See graph in attachment

The appropriate graph to draw in this part is a graph of velocity vs time.

In this problem, we have a horse that accelerates from 0 m/s to 15 m/s in 10 s.

Assuming the acceleration of the horse is uniform, it means that the velocity (y-coordinate of the graph) must increase linearly with the time: therefore, the velocity-time graph will appear as a straight line, having the final point at

t = 10 s

v = 15 m/s

(b) 1.5 m/s^2

The average acceleration of the horse can be calculated as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 0

v = 15 m/s

t = 10 s

Substituting,

a=\frac{15-0}{10}=1.5 m/s^2

(c) 75 m

For a uniformly accelerated motion, the distance travelled can be calculated by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time interval

a is the acceleration

In this problem,

u = 0

t = 10 s

a=1.5 m/s^2

Substituting,

s=0+\frac{1}{2}(1.5)(10)^2=75 m

(d) See attached graphs

In a uniformly accelerated motion:

- The distance travelled (x) follows the equation mentioned in part c,

x=ut+\frac{1}{2}at^2

So, we see that this has the form of a parabola: therefore, the graph x vs t will represents a parabola.

- The acceleration is constant during the motion, and its value is

a=1.5 m/s^2 (calculated in part b)

therefore, the graph acceleration vs time will show a flat line at a constant value of 1.5 m/s^2.

6 0
3 years ago
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