<span>For hydrolysis to monosaccharides, one molecule of a disaccharide needs only one molecule of water.
C12H22O11 (sucrose) + H2O = C6H12O6 (glucose) + C6H12O6 (fructose)
Structurally, a disaccharide molecule may be viewed as a product formed by the condensation of two molecules of monosaccharides with the elimination of a water molecule. So, only one H2O molecule is needed for the reverse process.</span>
I would think that you would multiply then divide
Work-Energy :W = 1/2 m ( Vf^2 -Vo^2 )
Vo = 24.0 m/s Initial speed
Vf = 27.5 m/s Final speed
W = 1/2 m ( Vf^2 -Vo^2 )
160 kj = 1/ 2 m ( 27.5^2 -24.0 ^2)
160kj = 4680 x m
convert kilo joules to jeoules 160000 j = 4689 xm
m = 160000 j/4689
m = 34.18 kg
Air resistance is the answer
(a) Zero
The maximum efficiency (Carnot efficiency) of a heat engine is given by
where
is the low-temperature reservoir
is the high-temperature reservoir
For the heat engine in the problem, we have:
Therefore, the maximum efficiency is
(b) Zero
The efficiency of a heat engine can also be rewritten as
where
W is the work performed by the engine
is the heat absorbed from the high-temperature reservoir
In this problem, we know
Therefore, since the term cannot be equal to infinity, the numerator of the fraction must be zero as well, which means
W = 0
So the engine cannot perform any work.
