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daser333 [38]
2 years ago
10

Can you solve the chart?

Mathematics
1 answer:
Travka [436]2 years ago
4 0

Answer:

i dont know  sorry  bro

Step-by-step explanation:

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Math question, note: there are two answers!!
stiks02 [169]

The answer is A and B.  I showed my work below.  I hope it makes sense.  Let me know if you have any questions.

5 0
3 years ago
For every 15 students there are 3 teachers in the school. Based on this information, about how many teachers are in a school wit
Yuliya22 [10]
This means for every 5 students there will be 1 teacher so 550/5=110
So answer is 110 teachers
3 0
2 years ago
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New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
Nemos aquarium is filled with 2400 cm of water the base of the aquarium is 20 cm long and 12 cm wide what is the height of the w
SSSSS [86.1K]

The answer to this question is 10 cm

In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).

Then you need to divide the volume with the length and width. The equation would be:

Aquarium height= volume / length / width

Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.

7 0
3 years ago
5 DIVIDED BY 1/4 hURRY PLEASE
Anni [7]

Hello!

1/4 is equal to 0.25. Let's divide below.

5/0.25=20

When dividing by fractions, you multiply by the reciprocal. The reciprocal of 1/4 is 4, and 5(4)=20

Therefore, our answer is 20.

I hope this helps!

6 0
3 years ago
Read 2 more answers
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