1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MA_775_DIABLO [31]
3 years ago
14

Classify the possible combinations of signs for a reaction's ΔH and ΔS values by the resulting spontaneityA. ΔH is positive and

ΔS is negativeB. ΔH is positive and ΔS is positiveC. ΔH is negative and ΔS is positiveD. ΔH negative and ΔS is negativeFor A, B, C and D find out which of following they are:1. Spontaneous as written at all temperatures2. Spontaneous in reverse at all temperatures3. Spontaneous as written above a certain temperature4. Spontaneous as written below a certain temperature
Chemistry
1 answer:
sergejj [24]3 years ago
3 0

Explanation:

1. Spontaneous as written at all temperatures

C. When ΔH is negative and ΔS is positive, the sign of ΔG will always be negative, and the reaction will be spontaneous at all temperatures.

2. Spontaneous in reverse at all temperatures

A. When ΔH is positive and ΔS is negative, the sign of ΔG will always be positive, and the reaction can never be spontaneous.

3. Spontaneous as written above a certain temperature

B. ΔH is positive and ΔS is positive - an endothermic reaction (positive ΔH) that also displays an increase in entropy (positive ΔS). It is the entropy term that favors the reaction. Therefore, as the temperature increases, the TΔS term in the Gibbs free energy equation will begin to predominate and ΔG will become negative.

4. Spontaneous as written below a certain temperature

D. ΔH negative and ΔS is negative -  When the reaction is exothermic (negative ΔH) but undergoes a decrease in entropy (negative ΔS), it is the enthalpy term which favors the reaction. In this case, a spontaneous reaction is dependent upon the TΔS term being small relative to the ΔH term, so that ΔG is negative. The freezing of water is an example of this type of process. It is spontaneous only at a relatively low temperature.

You might be interested in
Can reactions be more than one of the five types
ehidna [41]
Yes you can it will not just have 5 :)

3 0
3 years ago
Acids or bases can be tested by chemical_________
DedPeter [7]

Answer:

acids or bases can be tested

by chemical indicators

7 0
2 years ago
Read 2 more answers
How many moles of potassium nitrate, KNO3 are present in a sample with a mass of 85.2 g?
Bingel [31]
0.843 moles would be the answer
5 0
3 years ago
A container of hydrogen gas has the same temperature as a container of oxygen gas. The gas atoms having the greater average kine
user100 [1]

Answer:

hope this helps

Explanation:

The atoms of hydrogen have smaller mass than oxygen. Thus their speeds have to higher in order to produce the same average kinetic energies.

4 0
2 years ago
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.</em>

<em />

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

<em>The moles of CH3COO- are its initial moles - the moles of HCl added</em>

<em>And moles of CH3COOH are its initial moles + moles HCl added</em>

<em />

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

<em>pH = 3.90</em>

<em />

<h3>The pH of the buffer is 3.90</h3>
3 0
3 years ago
Other questions:
  • How many grams of H2 will be produced from 12 grams of Mg according to the following equation?
    6·1 answer
  • You have a partially filled party balloon with 2.00 g of helium gas. you then add 2.74 g of hydrogen gas to the balloon. assumin
    8·1 answer
  • Nickel is extracted from nickel oxide by reduction with carbon.
    12·1 answer
  • For the following questions, use a periodic table and your atomic calculations to find the unknown information about each isotop
    7·1 answer
  • Answer question number 7
    6·2 answers
  • Hekehwkhekehekhdkfnflebkdkfbrkebekebe
    8·2 answers
  • PLEASE HELP!!!!!!!!!
    8·1 answer
  • in the diagram shown below, the blue light ray represents a ray of light incident on a boundary between media. the diagram repre
    10·1 answer
  • Determine the location of the last significant place value by placing a bar over the digit.
    6·1 answer
  • Competitive inhibition occurs when a
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!