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MA_775_DIABLO [31]
3 years ago
14

Classify the possible combinations of signs for a reaction's ΔH and ΔS values by the resulting spontaneityA. ΔH is positive and

ΔS is negativeB. ΔH is positive and ΔS is positiveC. ΔH is negative and ΔS is positiveD. ΔH negative and ΔS is negativeFor A, B, C and D find out which of following they are:1. Spontaneous as written at all temperatures2. Spontaneous in reverse at all temperatures3. Spontaneous as written above a certain temperature4. Spontaneous as written below a certain temperature
Chemistry
1 answer:
sergejj [24]3 years ago
3 0

Explanation:

1. Spontaneous as written at all temperatures

C. When ΔH is negative and ΔS is positive, the sign of ΔG will always be negative, and the reaction will be spontaneous at all temperatures.

2. Spontaneous in reverse at all temperatures

A. When ΔH is positive and ΔS is negative, the sign of ΔG will always be positive, and the reaction can never be spontaneous.

3. Spontaneous as written above a certain temperature

B. ΔH is positive and ΔS is positive - an endothermic reaction (positive ΔH) that also displays an increase in entropy (positive ΔS). It is the entropy term that favors the reaction. Therefore, as the temperature increases, the TΔS term in the Gibbs free energy equation will begin to predominate and ΔG will become negative.

4. Spontaneous as written below a certain temperature

D. ΔH negative and ΔS is negative -  When the reaction is exothermic (negative ΔH) but undergoes a decrease in entropy (negative ΔS), it is the enthalpy term which favors the reaction. In this case, a spontaneous reaction is dependent upon the TΔS term being small relative to the ΔH term, so that ΔG is negative. The freezing of water is an example of this type of process. It is spontaneous only at a relatively low temperature.

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tigry1 [53]

Answer:

It has been drawn and uploaded as an attachment. Please download it to see the structure.

Explanation:

The product formed as a result of the reaction of cyclohexene with H2​ in presence of Pt (platinum) can be described as catalytic hydrogenation. Catalytic hydrogenation is defined as the process of hydrogen addition in the presence of a catalyst, which in this case is platinum.

Note that Cyclohexene (alkene) is a hydrocarbon molecule represented by the chemical formula, C6​H10​ .

It consists of a double bond. During the hydrogenation reaction, the alkene undergoes an addition reaction to give alkane which is a saturated hydrocarbon as the product.

The first step in order to derive the product is to draw the chemical structure of cyclohexene and identify the double bond present in it.

The final product can be derived by replacing the double bond with the single bond and satisfying all the valences of the carbon atom. The final product structure has been drawn and uploaded as an attachment. Please download it to see the structure.

Ans:

The structure of the cyclohexane thus, formed has been shown as follows with all the hydrogen atoms:

3 0
3 years ago
Density is d= m/vol. If a material has a mass of 65.5 g and a volume of 32.5 ml, it has a density of
ryzh [129]

Using the given formula, the density of the material is 2.015 g/mL

<h3>Calculating Density </h3>

From the question, we are to determine the density of the material

From the given formula

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And from the given information,

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and volume = 32.5 mL

Putting the parameters into the equation,

Density = 65.5/32.5

Density = 2.015 g/mL

Hence, the density of the material is 2.015 g/mL.

Learn more on Calculating density here: brainly.com/question/24772401

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Explanation:

(You can refer to the DMV triangle to help you solve this!)

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