It has a higher boiling point and a lower freezing point
Answer:
CS₂
Explanation:
To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:
<em>%C:</em>
0.33gC / 2.12g * 100 = 15.6%
<em>%S:</em>
1.53g S / 1.82g * 100 = 84.1%
In a basis of 100, the moles of each atom are:
<em>C:</em>
15.6g C * (1mol / 12.01g) = 1.30 moles
<em>S:</em>
84.1g S * (1mol / 32.065g) = 2.62 moles
The ratio of Sulphur-Carbon is:
2.62mol / 1.30mol = 2
That means empirical formula is:
<h3>CS₂</h3>
Answer:
CaF2 + CO3- ----> CaCO3 + 2 F-
Explanation:
The chemical compounds found on the left side of the date are the reagents and those found on the right are the products, where calcium carbonate appears.
Calcium carbonate is a quaternary salt
Answer:
Explanation:
CaI₂(s) ⟶ Ca²⁺ + 2I⁻
1. Original concentration of I⁻
The chemist diluted 20 mL of the original solution to 100 mL
We can use the dilution formula to calculate the original concentration of I⁻.
2. Original concentration of Ca²⁺
The molar ratio is 1 mol Ca²⁺:2 mol I⁻.
![[\text{Ca}^{2+}] =\dfrac{2.87 \times 10^{-5} \text{ mol I}^{-}}{\text{1 L}} \times \dfrac{\text{1 mol Ca}^{2+} }{\text{2 mol I}^{-}} = \mathbf{1.44 \times 10^{-5}} \textbf{ mol/L}\\\\\text{[Ca$^{2+}$] in the original solution was $\large \boxed{\mathbf{1.44 \times 10^{-5}} \textbf{ mol/L}}$}](https://tex.z-dn.net/?f=%5B%5Ctext%7BCa%7D%5E%7B2%2B%7D%5D%20%3D%5Cdfrac%7B2.87%20%5Ctimes%2010%5E%7B-5%7D%20%5Ctext%7B%20mol%20I%7D%5E%7B-%7D%7D%7B%5Ctext%7B1%20L%7D%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20Ca%7D%5E%7B2%2B%7D%20%7D%7B%5Ctext%7B2%20mol%20I%7D%5E%7B-%7D%7D%20%3D%20%5Cmathbf%7B1.44%20%5Ctimes%2010%5E%7B-5%7D%7D%20%5Ctextbf%7B%20mol%2FL%7D%5C%5C%5C%5C%5Ctext%7B%5BCa%24%5E%7B2%2B%7D%24%5D%20in%20the%20original%20solution%20was%20%24%5Clarge%20%5Cboxed%7B%5Cmathbf%7B1.44%20%5Ctimes%2010%5E%7B-5%7D%7D%20%5Ctextbf%7B%20mol%2FL%7D%7D%24%7D)
