Earth's atmosphere is 78% nitrogen, 21% oxygen, 0.9% argon, and 0.03% carbon dioxide with very small percentages of other elements. Our atmosphere also contains water vapor. In addition, Earth's atmosphere contains traces of dust particles, pollen, plant grains and other solid particles.
The heat (Q) required to raise the temp of a substance is:<span>Q=m∗Cp∗ΔT</span><span> where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
</span><span>1380.72 Joules</span>
Answer:
The volume will be 0.031 L
Explanation:
Since temperature is constant, Boyle's law is applied in this case.
Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.
From this statement it was deduced that P1V1 = P2V2
From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.
V2 = P1V1/P2
= 1×1.55÷50
=0.031 L
If the item or substance has changed into a state where you are able to change it back such as:
Water melting
Water freezing
V = 60.0 g/ 0.70 g/mL = 85.7 mL Hope this helps! ;D
