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Tema [17]
4 years ago
10

If f=(2,3),(5,7),(5,4),(9,1), what is the range

Mathematics
2 answers:
Inga [223]4 years ago
4 0

Answer:

The range of f is {1 , 3 , 4 , 7}

Step-by-step explanation:

* Lets revise the relation

- f is a relation between x and y

- x is the input of the relation

- y is the output of the relation

- x is called the domain of the relation

- y is called the range of the relation

- The range is the corresponding value to x

* Now lets solve the problem

∵ f = {(2 , 3) , (5 , 7) , (5 , 4) , (9 , 1)

∵ x = {2 , 5 , 9}

∴ The domain of f is {2 , 5 , 9}

∵ y = {1 , 3 , 4 , 7}

∴ The range of f is {1 , 3 , 4 , 7}

lbvjy [14]4 years ago
3 0

Answer:  Range:{1,3,4,7}

Step-by-step explanation:

We know that, by definition, the Domain is the set of all the x-coordinates of the ordered pairs  and the Range is the set of all the y-coordinates of the ordered pairs.

Therefore, given f=(2,3),(5,7),(5,4),(9,1), you can observe that the set of all second elements of ordered pairs (the values of "y") is the following:

{3,7,4,1}

 Therefore, we can conclude that if f=(2,3),(5,7),(5,4),(9,1) , then the range is:

 Range:{1,3,4,7}

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bulgar [2K]

Question is not proper, Proper question is given below;

36% of the beans in Pythagoras's soup are lentils, and 33 1/3% of those lentils are green.

If Pythagoras removes all green lentils from his soup, then x% of the original beans remain. What is x?

Answer:

88% of the original beans remains (x) after removing green lentils.

Step-by-step explanation:

Given:

Let the Original beans be 'n'.

Now given:

36% of the beans in Pythagoras's soup are lentils.

So we can say that;

Amount of lentils = \frac{36}{100}n=0.36n

Also Given:

33 1/3% of those lentils are green

Amount of green lentils = 33\frac{1}{3}\%\ \ Or \ \ \frac{100}{3}\%

Amount of green lentils = \frac{100}{3}\times 0.36n\times\frac{1}{100}= 0.12n

Now we need find the percentage of original beans remain after removing green lentils.

Solution:

percentage of original beans remain  ⇒ x\%

To percentage of original beans remain after removing green lentils we will subtract Amount of green lentils from Original beans  and then multiplied by 100.

framing in equation form we get;

x\% = (n-0.12n)\times 100=88n \ \ \ Or \ \ \ 88\%

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<u>Given information</u>

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<u>Substitute values into the equation</u>

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