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3 years ago

If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.

Mathematics

1 answer:

larisa86 [58]3 years ago

8 0

Answer:

The answer is

<h2>2√74 or 17.20 units</h2>

Step-by-step explanation:

The length of w line segment between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(-8, 7) and T (6,-3)

The length of ST is

$|ST| = \sqrt{ ({ - 8 - 6})^{2} + ({7 + 3})^{2} } \\ = \sqrt{ ({ - 14})^{2} + {10}^{2} } \\ = \sqrt{196 + 10} \\ = \sqrt{296} \\ = 2 \sqrt{74} \\ = 17.2046505...$

We have the final answer as

<h3>2√74 or 17.20 units</h3>

Hope this helps you

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5 ft is ____ % of 37 1 2 ft; 37 1 2 ft is ____ % of 5 ft

hichkok12 [17]

Answer:

The answer is:

5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

Step-by-step explanation:

Given:

5 ft is ____ % of 37 1 2 ft.

Now, to find the __ :

Let __ be $x.$

So, 5 ft is $x\%$ of 37 1/2

$5=x\% of 37\frac{1}{2}$

⇒ $5=\frac{x}{100} \times \frac{75}{2}$

⇒ $5=\frac{75x}{200}$

Multiplying both sides by 200 we get:

⇒ $1000=75x$

Dividing both sides by 75 we get:

⇒ $13.33=x$

⇒ $x=13.33\%.$

Now, 37 1/2 ft is $x$ % of 5 ft.

$\frac{75}{2} =x\%\ of\ 5$

$\frac{75}{2}=\frac{x}{100}\times 5$

$\frac{75}{2} =\frac{5x}{100}$

Multiplying both sides by 100 we get:

$\frac{7500}{2} =5x$

Dividing both sides by 5 we get:

$750=x$

$x=750\%$

Therefore, the answer is 5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

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2 years ago

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Inessa05 [86]

Answer:

Step-by-step explanation:

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Hint:

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Answer:

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2 years ago

If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.​

If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.