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3 years ago

in a box were put ten balls , 4 white , 3 blue , 2 red and 1 black . Withdrawing only 4 , as there are combinations

Mathematics

1 answer:

Basile [38]3 years ago

5 0

The most likely color to be grabbed is the white ones because there are more

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If e^(xy) = 2, then what is dy/dx at the point (1, ln2)?

love history [14]

E^(xy) = 2
(xdy/dx + y)e^(xy) = 0

At point (1, ln2), dy/dx + ln2 = 0
dy/dx = -ln2

3 0

3 years ago

3(2x + 5)2(x + 6)<br> Can someone help me :)

Mamont248 [21]

Answer:

6x+15>2x+12

6x-2x>12-15

4x>-3

x>-3/4

Step-by-step explanation:

6 0

3 years ago

0 = -5x + 4y in standard form

Effectus [21]

Answer:

5x - 4y = 0

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given 0 = - 5x + 4y ( multiply through by - 1 )

5x - 4y = 0 ← in standard form

6 0

3 years ago

Read 2 more answers

2x+10=5y-4 solve for x

scoundrel [369]

Answer: x=2.5y-7

Step-by-step explanation:

Subtract 10 from both sides, resulting in 2x=5y-14

Divide both sides by 2 to isolate the x, resulting in x=(5/2)y-7

5 0

3 years ago

Using the quadratic formula, solve 0 = 2x² - 10x + 7<br> Give each of your answers to 2 d.p.

xenn [34]

Answer:

$\sf \: x = \frac{5}{2} + \frac{ ± 1}{2} \sqrt{11}$

Step-by-step explanation:

Let's solve your equation step-by-step.

0=2x²−10x+7

Step 1: Subtract 2x^2-10x+7 from both sides.

0−(2x²−10x+7)=2x²−10x+7−(2x²−10x+7)

−2x²+10x−7=0

For this equation: a=-2, b=10, c=-7

−2x²+10x+−7=0

Step 2: Use quadratic formula with a=-2, b=10, c=-7.

$\sf \: x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a}$

$\sf \: x = \frac{ - (10)± \sqrt{ {10}^{2} - 4( - 2)( - 7) } }{2( - 2)}$

$\sf \: x = \frac{ - 10 ± \sqrt{44} }{ - 4}$

$\sf \: x = \frac{5}{2} + \frac{ ± 1}{2} \sqrt{11}$

5 0

1 year ago