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3 years ago

3(2x + 5)2(x + 6) Can someone help me :)

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

Answer:

6x+15>2x+12

6x-2x>12-15

4x>-3

x>-3/4

Step-by-step explanation:

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I don't get the problem

Ulleksa [173]

A(b + c) = a*(b + c) = a*b + a*c

You must multiply individual terms and see what it would equal

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2 years ago

Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

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3 years ago

What are the vertex and x-intercepts of the graph of the function given below?

valentinak56 [21]

Hello :
x²-2x-24 =( x²-2x+1)-1-24
= (x-1)² -25 ..... ( vertex form)
. Vertex: (1, -25);
intercepts: x = 6, -4 because :
f(x) = 0..... (x-1)² -25 =0
(x-1)² = 5²
x-1=5 or x-1 = -5
x=6 or x=-4

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2 years ago

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rosijanka [135]

Answer:

The answer is 2

Step-by-step explanation:

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3 years ago