Answer:
16.6 kJ/°C
Explanation:
given,
Amount of heat absorbed = 45 kJ
initial temperature, T₁ = 25.5°C
final temperature, T₂ = 28.2°C
change in temperature = T₂ - T₁
= 28.2 - 25.5 = 2.7° C
Heat capacity of the object is equal to 16.6 kJ/°C
Answer:
Hence the weight of the person on the moon is 162.4, and the value of g used is 1.624 m/s²
Explanation:
from the question,
W = mg........................ Equation 1
Where W = weight of the man on Earth, m = mass of the man, g = acceleartion due to gravity of the man
make m the subject of the equation
m = W/g.............. Equation 2
Given: W = 1000 N,
Constant: g = 10 m/s²
Therefore,
m = 1000/10
m = 100 kg
Weight on the moon
W' = mg'
W' = 100(1.624)
W' = 162.4 N.
Hence the weight of tthe person on the moon is 162.4, and the value of g used is 1.624 m/s²
Answer: 0.36 meter per second square
Explanation from hooke's law f = ke
from motion, F=ma
Ma=me
Where a= ?
K=300
e=0.6
M=500kg
500×a =300×0.6
a = 180÷500
a = 0.36 meter per second square
Answer: 30 meters
Explanation: 5 meters times 7 seconds
