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eduard
3 years ago
7

How does the angle of launch affect the kinetic energy of a rubber band?​

Physics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

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Corrosion is the tendency of a metal to revert back to its natural state.
algol13
Corrosion is the irreversible damage or destruction of living tissue or material due to a chemical or electrochemical reaction.
3 0
3 years ago
PLEASEEE HELPPP!!!
Alja [10]

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is :

W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m

Hence, this is the required solution.

3 0
3 years ago
If vx=9.80 units and vy=-6.40 units, determine the magnitude and direction of v
dexar [7]
The resultant vector can be determined by the component vectors. The component vectors are vector lying along the x and y-axes. The equation for the resultant vector, v is:

v = √(vx² + vy²)
v = √[(9.80)² + (-6.40)²]
v = √137 or 11.7 units
5 0
4 years ago
A man pushes a 10kg box with a constant acceleration of 5m/s2. What force is applied to the box?
drek231 [11]
FORMULA

\boxed {F = m \times a}

F = force
m = mass
a = acceleration

Using the formula

F = 10 \times 5

Multiply

\boxed {\textsf {F = 10 N}}
8 0
3 years ago
Read 2 more answers
A child is sitting on the outer edge of a merry-go-round that is 1.5 m in diameter. If the merry-go-round makes 3.2 rev/min, wha
Troyanec [42]

Answer:

the velocity of the kid is 5.6 m/s

Explanation:

r is the radius and w is the frequency.

so we should know that the diameter is 18m and the diameter is equal to two times the radius, so r = 18m/2 = 9m

we should also know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length. if the kid does 5.9 revolutions in one minute then the kid spins at v = 5.9*2pi*9m/min

so we want to write this in meters per second and this means that we need to divide it by 60!

v = (5.9*2pi*9/60)m/s = 5.56 m/s

so your answer will be  5.6 m/s glad i could help!

4 0
2 years ago
Read 2 more answers
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