Answer:
pressure of water will be 49.7 atm
Explanation:
given data
pressure = 30 psi = 2.04 atm
water = 2 pound = 907.18
mole of water vapor = 907.19 /2 = 50.4 mole
volume = 4 ft³ = 113.2 L
temperature = 40 F = 277.59 K
to find out
pressure of water
solution
we will apply here ideal gas condition
that is
PV = nRT .......................1
put here all value and here R = 0.0821 , T temperature and V volume and P pressure and n is no of mole
and we get here temperature
PV = nRT
2.04 × 113.2 = 50.4×0.0821×T
solve it and we get
T = 55.8 K
so we have given right chamber has twice the volume of the left chamber i.e
volume = twice of volume + volume
volume = 2(113.2) + 113.2
volume = 339.6 L
so from equation 1 pressure will be
PV = nRT
P(339.6) = 50.4 × ( 0.0821) × (277.59)
P = 3.3822 atm = 49.7 atm
so pressure of water will be 49.7 atm
