I think it’s air pressure
It will be unaffected by the magnet because it has no magnetic field. If you were to maybe have electricity going through it is the only way it would have anything to do with the magnet.
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Answer:
19.29 m/s
Explanation:
Apply the conservation of linear momentum in north-south direction:
![m_pv_p+m_ev_e sin \theta = (m_p+m_e)v_f sin \phi\\m_p (17.3)+(2m_p)(33.7 sin (-39.9))=3m_p v_f sin \phi\\17.3-43.23=3v_fsin\phi\\\Rightarrow v_f sin\phi = -8.64](https://tex.z-dn.net/?f=m_pv_p%2Bm_ev_e%20sin%20%5Ctheta%20%3D%20%28m_p%2Bm_e%29v_f%20sin%20%5Cphi%5C%5Cm_p%20%2817.3%29%2B%282m_p%29%2833.7%20sin%20%28-39.9%29%29%3D3m_p%20v_f%20sin%20%5Cphi%5C%5C17.3-43.23%3D3v_fsin%5Cphi%5C%5C%5CRightarrow%20v_f%20sin%5Cphi%20%3D%20-8.64)
Apply the conservation of linear momentum in east-west direction:
![m_ev_e cos \theta = (m_p+m_e)v_f cos \phi\\2m_p (33.7)cos (39.9) = 3 m_pv_f cos\phi\\\Rightarrow v_f cos\phi = 17.23](https://tex.z-dn.net/?f=m_ev_e%20cos%20%5Ctheta%20%3D%20%28m_p%2Bm_e%29v_f%20cos%20%5Cphi%5C%5C2m_p%20%2833.7%29cos%20%2839.9%29%20%3D%203%20m_pv_f%20cos%5Cphi%5C%5C%5CRightarrow%20v_f%20cos%5Cphi%20%3D%2017.23)
Dividing the two equations:
![tan \phi = \frac{-8.64}{17.23} \\\phi = -26.6^o](https://tex.z-dn.net/?f=tan%20%5Cphi%20%3D%20%5Cfrac%7B-8.64%7D%7B17.23%7D%20%5C%5C%5Cphi%20%3D%20-26.6%5Eo)
![v_f sin \phi = -8.64 \\v_f = \frac{-8.64}{sin (-26.6^o)} = 19.29 m/s](https://tex.z-dn.net/?f=v_f%20sin%20%5Cphi%20%3D%20-8.64%20%5C%5Cv_f%20%3D%20%5Cfrac%7B-8.64%7D%7Bsin%20%28-26.6%5Eo%29%7D%20%3D%2019.29%20m%2Fs)
Thus, the speed of the eagle immediately after it catches its prey is 19.29 m/s.
Answer:
The correct order of events over time