Answer:
balanced equation mole ratio 5 2 mol NO/1 mol O2
10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2
20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO
actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2
Because the actual mole ratio of NO:O2 is larger than the balanced equation mole
ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.
Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO
0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO
Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2
Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N
Explanation:
Answer:
O, N, C, H
Explanation:
Electronegativity of an element is the property that combines the ability of its atom to lose or gain electrons. It measures the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
On the periodic table, Electronegativity increases across the period but decreases down a group.
To solve the given problem, let us use thE Pauling's table of electronegativities to compare the electronegativities of the elements.
On the table:
C = 2.5
H = 2.1
O = 3.5
N = 3.0
In terms of decreasing electronegativities, the atoms are arranged as:
O N C H
Moles ratio:
1 S<span> + 1 </span><span>O2</span><span> = 1 </span><span>SO<span>2
</span></span>
1 mole S -------------- 1 mole SO2
? moles S ------------ 0.567 moles SO2
0,567 x 1 / 1
= 0.567 moles of S
