A-leads to the abrasion of rocks and minerals
A-dense vegetation cover
True
Explanation:
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Agent of weathering are wind, water and glacier.
Chemical weathering contributes to physical weathering in that it leads to the abrasion of rocks and minerals.
During chemical weathering, a rock chemically combines with materials in the environment and weakens it.
When physical weathering processes are induced, grains produced independently weakening of bonds in rocks grind against one another and wears each other off.
An area with a dense vegetation cover undergoes rapid chemical weathering:
- Plant roots penetrates deep into the rock and increases the surface area of chemical action.
- Plants produce chemicals that combines with rocks and causes them to decay.
- Since the area is always moist, chemical action becomes more severe.
Buildings and statues made of stone are subjected to the same degree of weathering as rocks exposed naturally.
This is true.
Statues and buildings weather just like rocks we find in nature.
It is the same sunshine and rain that impacts rocks that also impacts buildings and statues.
So they degrade at the same rate except they are protected.
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Answer:
0.5832 miles =3079ft and 3.552 inches
Explanation:
This is if you are wanting the foot amount and the extra in inches, if you are wanting it in just feet and just inches it would be 3079.296 feet and 36951.552 inches
Answer:
869 g Cl₂O
Explanation:
To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).
1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)
Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol
Molar Mass (Cl₂O): 86.904 g/mol
10.0 moles SO₂ 1 mole Cl₂O 86.904 g
------------------------ x ---------------------- x ------------------ = 869 g Cl₂O
1 mole SO₂ 1 mole
<u>Answer:</u> The solubility product of silver (I) phosphate is 
<u>Explanation:</u>
We are given:
Solubility of silver (I) phosphate = 1.02 g/L
To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:
Molar mass of silver (I) phosphate = 418.6 g/mol
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The chemical equation for the ionization of silver (I) phosphate follows:
3s s
The expression of 
for above equation follows:
We are given:
Putting values in above expression, we get:
Hence, the solubility product of silver (I) phosphate is
Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
Explanation:
A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.
Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.
This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.
So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.
- As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.
- Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.
- Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.
Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
