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2 years ago

6

Jupiter’s Great Red Spot rotates completely every six days. If the spot is circular (not quite true, but a reasonable approximat

ion for this matter) and 26,000 km in diameter, what are the wind speeds (i.e. how fast the gas is moving) at the outer edges ofthe storm (in km/hr)? (Hints: Recall the definition of speed. Think about how far a cloud on the edge of the storm must travel.)

1 answer:

artcher [175]2 years ago

5 0

Answer:

$v = 567.2 km/h$

Explanation:

As we know that if Jupiter Rotate one complete rotation then it means that the it will turn by 360 degree angle

so here the distance covered by the point on its surface in one complete rotation is given by

$distance = 2\pi r$

$distance = \pi D$

now we will have the time to complete the rotation given as

$t = 6 days$

$t = 6 (24 h) = 144 h$

now the speed is given by

$speed = \frac{distance}{time}$

$speed = \frac{\pi D}{t}$

$speed = \frac{\pi(26000 km)}{144}$

$v = 567.2 km/h$

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