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madam [21]
3 years ago
13

Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.09 How much work is done by t

he clectric force when a sodium ion charge d e s brore the outside to the inside Number Units the tolerance is */-2%
Physics
1 answer:
DENIUS [597]3 years ago
3 0

Answer:

1.44\cdot 10^{-20} J

Explanation:

The difference in electric potential between the inside and the outside of the cell is

\Delta V = 0.09 V

The work done by the electric force to bring the ion from outside to inside is

W=q\Delta V

where

q is the charge of the ion

A sodium ion, Na^+, has given off an electron: so its electric charge is

q=+e=+1.6\cdot 10^{-19} C

Therefore, the work done is:

Q=(1.6\cdot 10^{-19})(0.09)=1.44\cdot 10^{-20} J

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Answer:

surface temperature of the chip located 120 mm Ts=42.5°C

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Explanation:

from the energy balance equation we have to:

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Ts=Tα+(q/(h*A)), where A=l^2

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the surface temperature at Mexico City is equal to:

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