Answer: C
Period/ Period of the pendulum.
Content:
Simple pendulum is a small diameter bob which is suspended from light cord or string. The string is strong enough to stretch.
Pendulums are quiet common in use such as clocks, swings etc.,
From the simple pendulum we can find conditions under which it performs simple harmonic motion and we can also derive the expressions for Period of pendulum, frequency etc.
<em>Period of a pendulum/Time period is given by the following expression</em>
<em> </em><em> T =2π.√(L/g) seconds </em>
<em> </em><em>T = period of pendulum in seconds</em>
<em> L = Length of the string/cord in meters</em>
<em> g = gravitational force in m/s² ( g = 9.8 m/s² )</em>
<em>Period of pendulum is independent on mass of the bob.</em>
<em>So, The relation between length of the cord and gravity is used to determine the period of pendulum</em>
Answer:
Option B. The distance between the objects in Figure A is shorter than the distance between the objects in Figure B.
Explanation:
The force of attraction between two masses is given by the following equation:
F = GM₁M₂ / r²
Where:
F => is the force of attraction
M₁ and M₂ => are the masses of the two objects
G => is the gravitational constant.
r => is the distance between the two objects
From the above formula,
The force of attraction (F) is directly proportional to the product of the two masses and inversely proportional to the square of their apart.
This implies that:
1. An increase in the masses of the object will bring about an increase in the force of attraction and a decrease in the masses will leads to a decrease in the force of attraction.
2. An increase in the distance between the two masses will leads to a decrease in the force of attraction and a decrease in the distance between the two masses will lead to an increase in the force of attraction.
Considering the options given in the question above, option B gives the correct answer to the question.
That would be Cyanide.
Hope this helps! (:
The wavelength of the emitted photon is(
)= 690nm
<h3>How can we calculate the wavelength of the emitted photon?</h3>
To calculate the wavelength of the photon we are using the formula,
Or,
We are given here,
= The energy difference between the two levels = 1. 8 ev= 
C.
h= Planck constant = 
Js.
c= speed of light = 
m/s.
We have to find the wavelength of the emitted photon = m.
Therefore, we substitute the known parameters in the above equation, we can find that,
Or,
Or,
m
Or,=690 nm.
From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.
Learn more about ruby laser:
brainly.com/question/17245697
#SPJ4
In BPC
tan\theta =a/b = 3/4
\theta = tan^-1(0.75)
\theta = 36.87 deg
BP = sqrt(a^2 + b^2) = sqrt((3)^2 + (4)^2) = 5 m
Eb = k Q/BP^2 = (9 x 10^9) (16 x 10^-9)/5^2 = 5.76 N/C
Ea = k Q/AP^2 = (9 x 10^9) (16 x 10^-9)/4^2 = 9 N/C
Ec = k Q/CP^2 = (9 x 10^9) (16 x 10^-9)/3^2 = 16 N/C
Net electric field along X-direction is given as
Ex = Ea + Eb Cos36.87 = (9) + (5.76) Cos36.87 = 13.6 N/C
Net electric field along X-direction is given as
Ey = Ec + Eb Sin36.87 = (16) + (5.76) Sin36.87 = 19.5 N/C
Net electric field is given as
E = sqrt(Ex^2 + Ey^2) = sqrt((13.6)^2 + (19.5)^2) = 23.8 N/C
