Answer:
choice 4) 33.5 in³
Step-by-step explanation:
r = 4/2
V = 4/3πr³ = 4/3(3.14)(2³) = 33.5 in²
Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 
Answer:
y ≤ -4x+25
Step-by-step explanation:
First we need to figure out the equation for the line
The y intercept is 25
Next figure out the slope
slope = (y2-y1)/((x2-x1)
= (49-25)/(-6-0)
= 24/-6
= -4
The equation for a line in slope intercept form is y = mx+b
y = -4x+25
This is a solid line so our inequality will have an equals in it.
It is shaded below, so y is less than.
If it was shaded above, y would be greater than
y ≤ -4x+25