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3 years ago

15

When corn dogs are already made but they are cold do i need to fry them again or microwave it

1 answer:

Sergio [31]3 years ago

8 0

Microwave it! It just has to be defrosted.

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How many electrons can be held in sub level I=3?

Zinaida [17]

2 is your answer hope you get it right

6 0

3 years ago

A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th

pogonyaev

Answer:

$\boxed {\boxed {\sf 60 \%}}$

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

$\% \ yield= \frac {actual \ yield}{theoretical \ yield} *100$

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

$\% \ yield= \frac {12 \ L}{20\ L} *100$

$\% \ yield= 0.6*100$

$\% \ yield= 60$

For this reaction, the percent yield is 60%.

5 0

3 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

3 years ago

Your grandfather is a farmer. You hear him complain about how his crops are not doing well. You know that we have the same amoun

Firdavs [7]

Answer:

You may need better soil and a more plentiful amount of water coming from another source, and maybe find another way to contain the rain water

Explanation:you may need to draw it on paper sorry bout how it looks

4 0

3 years ago

Draw the R enantiomer of CFClBrI as a 3-D (wedge and dotted line) structure and as a Fischer projection (putting the I at the to

vazorg [7]

I don’t know This one is there a picture ?

4 0

3 years ago