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Karolina [17]
3 years ago
13

A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper

ature of the mixture is chosen so that Kp = 0.12. Predict the effect on the partial pressure of SO3 as equilibrium is achieved by using Q, the reaction quotient.
Chemistry
1 answer:
Anit [1.1K]3 years ago
4 0

Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

Equation for reaction quotient is as follows.

         Q = \frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}

             = \frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}

             = 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

  • This means that there are too much products.
  • Equilibrium will shift to the left towards reactants.
  • More SO_{3} is formed.
  • Partial pressure of SO_{3} increases.
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<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

<u>Explanation:</u>

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

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We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.100M

Putting values in above equation, we get:

pH=-\log(0.100)\\\\pH=1

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

pOH=14-1=13

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3. The temperature of a fixed mass of gas in a rigid container is decreased from 127.00 degrees
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Answer:

750mmHg

Explanation:

The following data were obtained from the question:

T1 = 127°C = 127 +273 = 400K

T2 = 27°C = 27 +273 = 300K

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P1/T1 = P2/T2

1000/400 = P2 /300

Cross multiply

400 x P2 = 1000 x 300

Divide both side by 400

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Assuming that the reaction from A and C to AC5 is only one-step (or an elementary reaction) with a balanced chemical reaction of:

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Substituting the given values into the equation:

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