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jekas [21]
3 years ago
14

What is the molar mass of Fe(NO3)2?

Chemistry
1 answer:
motikmotik3 years ago
5 0
I believe that the molar mass is 342.34g/mol
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What is the oxidation of KCL?
Assoli18 [71]

Rules:

1) The oxidation number of a monatomic ion equals the charge of the ion.

2)The oxidation number of a Group 1 element in a compound is +1.

3) The oxidation number of a Group 17 element in a binary compound is -1.

4) The sum of the oxidation numbers of all the atoms in a neutral compound is 0.

KCl is an ionic compound. Consists of K+ ions and Cl- ions.

Oxidation of K= +1 (rules 1 and 2)

Oxidation of Cl= -1 (rules 1 and 3)

Rule 4 also applies-  +1 + (-1)= 0- a neutral compound

Hope this helps :)

Explanation:

3 0
3 years ago
What is the difference between the crest and the trough of a wave?
Dominik [7]

Answer:

Trough is the lower bound of wave, while the crest is the upper bound of a wave.

Explanation:

see picture attatched

3 0
3 years ago
Please i need the answer for 18,19,20<br><br><br>Answer and I will give you brainiliest <br>​
dezoksy [38]
Number 18 is correct, number 19 is the particles speed up and the substance expands, and number 20 is decrease in volume
8 0
3 years ago
7. The grid in a triode is kept negatively charged to prevent A. electrons from escaping from the tube containing the triode. B.
romanna [79]

Answer:

A. Electrons from escaping from the tube containing the triode.

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Explanation:

5 0
3 years ago
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
3 years ago
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