Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
I believe the answer is D, only a small part of it
Answer:
Part a)
Velocity = 6.9 m/s
Part b)
Position = (3.6 m, 5.175 m)
Explanation:
Initial position of the particle is ORIGIN
also it initial speed is along +X direction given as
now the acceleration is given as
when particle reaches to its maximum x coordinate then its velocity in x direction will become zero
so we will have
Part a)
the velocity of the particle at this moment in Y direction is given as
Part b)
X coordinate of the particle at this time
Y coordinate of the particle at this time
so position is given as (3.6 m, 5.175 m)
Power = (voltage) x (current)
100w = 220v x current
Current = 100w / 220v = <u>0.455 Ampere</u> (rounded)
The answr is 5 changing mechanical to chemical
hope it helps
