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7nadin3 [17]
2 years ago
11

Is Kepler's constant the same for moons orbiting a planet as it is for planets orbiting the sun? Why?

Physics
2 answers:
d1i1m1o1n [39]2 years ago
7 0
Yes because we have day and night and seasons
baherus [9]2 years ago
6 0

The planets’ orbits are elliptical.

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Select the correct answer. An object has one force acting on it. It is a 33-newton force pointing downward. To create a net forc
kiruha [24]

Answer:

33 Newton upwards to get a net force of zero.

4 0
2 years ago
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1. Give three examples, from the lab, where potential energy was converted to kinetic energy: ​
Lubov Fominskaja [6]

Answer:

A book on a table before it falls.

A yoyo before it is released.

A raised weight.

Explanation:

These are all examples of potential energy. So I hope you can find something that is comparable from the lab.

3 0
3 years ago
The time constant of an RC circuit is 2.7 s. How much time t is required for the capacitor (uncharged initially) to gain 0.63 of
gayaneshka [121]

Answer:

2.7s

Explanation:

The solution of time required is shown below:-

In the RC circuit condenser charge 63 percent of the full charge from initial time to constant time

Now, the

63% that is equal to 0.63 which is full equilibrium charge

Therefore, the time required to maintain will be Equal to time (t) constant that is 2.7s

So, the correct answer is 2.7s

8 0
3 years ago
HELP QUICK PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
KIM [24]

Answer:

the answer is c

Explanation:

6 0
3 years ago
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a large sphere is on a horizontal field on a sunny day. at a certain time the shadow reaches out a distance of 10 m from the poi
Mars2501 [29]

The radius of the sphere in meters is ,r = 10\sqrt{5} -20

Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,

r/10 = tan [arctan(1/2)] = tan (1/2)

Since, tan (θ/2) = 1-cos(θ) / sin(θ)

we find that,

r/10 = \sqrt{5} -2

Hence, r = 10\sqrt{5} -20

So, the radius of the sphere in meters is ,r = 10\sqrt{5} -20

Learn more about radius (r) of the sphere here;

brainly.com/question/14100787

#SPJ4

5 0
1 year ago
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