Answer:
<em>The wavelength of water = 571.43 nm</em>
Explanation:
Refractive index of water = wave length of light in air/wave length of light in water
R.d = λ₁/λ₂.................. Equation 1
making λ₂ the subject of equation 1
λ₂ = λ₁/R.d...................... Equation 2
R.d = refractive index of water , λ₁ = wave length of light in air, λ₂ = wave length of light in water
<em>Given: R.d = 1.33, λ₁ = 760nm</em>
<em>Substituting these values into equation 2</em>
λ₂ = 760/1.33
<em>λ₂ = 571.43 nm</em>
<em>Therefore the wavelength of water = 571.43 nm</em>
Answer:
8.46E+1
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 39 C
Charge 2 (q₂) = –53 C
Force (F) of attraction = 26×10⁸ N
Electrical constant K) = 9×10⁹ Nm²/C²
Distance apart (r) =?
The distance between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
26×10⁸ = 9×10⁹ × 39 × 53 / r²
26×10⁸ = 1.8603×10¹³ / r²
Cross multiply
26×10⁸ × r² = 1.8603×10¹³
Divide both side by 26×10⁸
r² = 1.8603×10¹³ / 26×10⁸
r² = 7155
Take the square root of both side
r = √7155
r = 84.6 m
r = 8.46E+1 m
The angle of prism is 41.81 degrees.
<u>Explanation:</u>
For no emergence to be taken place, inside a prism, Total Internal Reflection (TIR) should take place at the second surface. For TIR, at second surface, angle of refraction must be greater than critical angle. Angle of prism is related to refraction as,
Since, 
= C and 
This implies 
when sin goes to other side become as sin inverse of value, and obtain the result as below,
