A circle has a revolution of 360°. Since there are 12 hour markings, each hour interval has an angle of 30°. In radians, that would be equal to π/6 radians. So, in every 1 hour that passes, it covers π/6 of an angle. So, the angular velocity denoted as ω is π/6 ÷ 1 hour = π/6 rad/h. We can compute the average linear velocity, v, from the relationship:
v = rω, where r is the radius of the circle which is the length of the hour hand
v = (2.4 cm)(π/6 rad/h)
v = 1.257 cm/hour
Therefore, the average velocity is 1.257 cm per hour.
For the average acceleration, it is equal to zero. The hands of the clock move at a constant velocity. Since acceleration is the change of velocity per unit time, there is no change of velocity because it's constant. That's why it is zero.
Wave A would have higher amplitude
Hope this helps :D
v is velocity, x is position, t is time, and a is acceleration.
Answer:
speed
Explanation:
Speed = distance travelled/time taken
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity, 
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :


I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :


I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :


I = 1688.31 kg-m²
The angular momentum of the system is :



So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.