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nirvana33 [79]
3 years ago
15

NEED HELP ASAP

Physics
1 answer:
Murljashka [212]3 years ago
8 0

Answer: 20.73 m/s

Explanation:

The centripetal force is given by the following equation:

F_{c}=m a_{c} (1)

Where:

F_{c}=2600 N is the centripetal force

m=1200 kg is the mass of the car

a_{c} is the centripetal acceleration

Isolating a_{c}:

a_{c}=\frac{F_{c}}{m} (2)

a_{c}=\frac{2600 N}{1200 kg} (3)

a_{c}=2.16 m/s^{2} (4)

Now, there is a relation between the centripetal acceleration and the tangential velocity:

a_{c}=\frac{V^{2}}{r} (5)

Where V is the tangential velocity and r is the radius of the circular path, which can be found if we know its length l=1.25 km=1250 m:

l=2 \pi r (6)

r=\frac{l}{2 \pi} (7)

r=\frac{1250 m}{2 \pi} (8)

r=198.94 m (9)

Substituting (4) and (8) in (5)

2.16 m/s^{2}=\frac{V^{2}}{198.94 m} (5)

Finding V:

V=20.729 m/s \approx 20.73 m/s

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Answer:

Mass

Explanation:

They have masses ranging from about 5 to several tens of solar masses.

8 0
4 years ago
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A sling is used to give a stone an initial velocity of 20 at an angle of 30 above the horizontal. The stone travels through the
Luba_88 [7]

Answer:

Option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile = 20 m/s

θ = angle above the horizontal at which the projectile was launched = 30°

g = acceleration due to gravity = 9.8 m/s²

R = (30² sin 60°) ÷ 9.8

R = 78.53 m

So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Hope this Helps!!!

7 0
4 years ago
At what speed, as a fraction of c, does a moving clock tick at four fifth the rate of an identical clock at rest?
ololo11 [35]

Answer:

The seed as a fraction of the speed of light is \frac{3}{5}c

Solution:

As per the question:

Suppose, t_{i} be the rate of an identical clock between two time intervals.

For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:

t = \frac{5}{4}t_{i}

Now,

Using the relation of time dilation, from Einstein's relation:

t = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

\frac{5}{4}t_{i} = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

Squaring both sides:

(\frac{5}{4})^{2} = (\frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}})^{2}

\frac{25}{16} = \frac{1}{{1 - \frac{v^{2}}{c^{2}}}}

1 - \frac{16}{25} = \frac{v^{2}}{c^{2}}

\frac{v}{c} = \sqrt{\frac{9}{25}}

\frac{v}{c} = \frac{3}{5}

v = \frac{3}{5}c

6 0
3 years ago
A plastic light pipe has an index of refraction of 1.48. For total internal reflection, what is the minimum angle of incidence i
Rama09 [41]

Answer:

a) 42.52°

b) 63.98°

Explanation:

Refractive index of pipe = 1.48 = n₂

Refractive index of air = 1.0003 = n₁

\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.0003}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.676\\\Rightarrow \theta_r=42.52^{\circ}

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∴ Minimum angle of incidence is 63.98°

5 0
4 years ago
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7 0
4 years ago
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