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nirvana33 [79]
3 years ago
15

NEED HELP ASAP

Physics
1 answer:
Murljashka [212]3 years ago
8 0

Answer: 20.73 m/s

Explanation:

The centripetal force is given by the following equation:

F_{c}=m a_{c} (1)

Where:

F_{c}=2600 N is the centripetal force

m=1200 kg is the mass of the car

a_{c} is the centripetal acceleration

Isolating a_{c}:

a_{c}=\frac{F_{c}}{m} (2)

a_{c}=\frac{2600 N}{1200 kg} (3)

a_{c}=2.16 m/s^{2} (4)

Now, there is a relation between the centripetal acceleration and the tangential velocity:

a_{c}=\frac{V^{2}}{r} (5)

Where V is the tangential velocity and r is the radius of the circular path, which can be found if we know its length l=1.25 km=1250 m:

l=2 \pi r (6)

r=\frac{l}{2 \pi} (7)

r=\frac{1250 m}{2 \pi} (8)

r=198.94 m (9)

Substituting (4) and (8) in (5)

2.16 m/s^{2}=\frac{V^{2}}{198.94 m} (5)

Finding V:

V=20.729 m/s \approx 20.73 m/s

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The object is not at a constant speed. It is either gaining speed or losing speed.

Explanation:

A speed-time graph measures how fast you are going in a certain amount of time.

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3 years ago
A standing wave on a string that is fixed at both ends has frequency 80.0 Hz. The distance between adjacent antinodes of the sta
OlgaM077 [116]

Answer:

v = 19.2 m/s

Explanation:

In order to find the speed of the string you use the following formula:

f=\frac{v}{2L}          (1)

f: frequency of the string = 80.0Hz

v: speed of the wave = ?

L: length of the string = 12.0cm = 0.12m

The length of the string coincides with the wavelength of the wave for the fundamental mode.

Then, you solve for v in the equation (1), and replace the values of the other parameters:

v=2Lf=2(0.12m)(80.0Hz)=19.2\frac{m}{s}

The speed of the wave is 19.2 m/s

8 0
4 years ago
Charges can be separated in an isolated system
Vesnalui [34]

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yes. can always be separated

4 0
3 years ago
Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
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goldenfox [79]

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kinetic mechanical energy

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