3 to the power of 4 +9
2 answers:
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K, so areitmetic
an=a1+d(n-1)
a1=first term
d=common differnce
we are given
a1=2 and 3/4
6th term is 3 and 7/12
so
a6=3 and 7/12=2 and 3/4+d(6-1)
3 and 7/12=2 and 3/4+d(5)
minus 2 and 3/4 both sides
10/12=5d
divide both sides by 5 or multiply both sides by 1/5
2/12=d
1/6=d
or
that is the rule
an=a1+d(n-1)
a1=first term
d=common differnce
we are given
a1=2 and 3/4
6th term is 3 and 7/12
so
a6=3 and 7/12=2 and 3/4+d(6-1)
3 and 7/12=2 and 3/4+d(5)
minus 2 and 3/4 both sides
10/12=5d
divide both sides by 5 or multiply both sides by 1/5
2/12=d
1/6=d
that is the rule