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Vikentia [17]
3 years ago
12

If the perimeter of triangle ABC is 4 more than the perimeter of triangle ACD, what is the perimeter of quadrilateral ABCD? AD i

s 5, DC is 6, AC is unknown, AB is unknown, CB is 7.
Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

26 units.

Step-by-step explanation:

AB + BC + AC = AC + AD + DC + 4

AC is common so

AB + BC = AD + DC + 4

AB + BC - AD - DC = 4

Substituting the given values

AB + 7 - 5 - 6 = 4

AB = 4 - 7 + 5 + 6 =  8

So the perimeter of ABCD

= AB + BC + AD + CD

= 8 + 7 + 5 + 6

= 26.

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The camp cook made 3 1/2 pints of baked beans. Each serving of beans is 1/2 of a pint. How many servings of beans did the cook m
Ilia_Sergeevich [38]

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The cook made 7 pints

Step-by-step explanation:

Just minus the half pints

5 0
3 years ago
Find the average rate of change for f(x) = x2 − 3x − 10 from x = 4 to x = 6. A) 5 Reactivate B) 7 C) 9 Reactivate D) 11
White raven [17]

Answer:Rate of change is 7

Option B is correct.

Step-by-step explanation:

We need to find the average rate of change for f(x)=x^2-3x-10 from x = 4 to x = 6

The formula used to find average rate of change is:

Rate\,\,of\,\,change=\frac{f(b)-f(a)}{b-a}

Where b = 6 and x = 4

Finding f(6):

f(x)=x^2-3x-10\\f(6)=(6)^2-3(6)-10\\f(6)=36-18-10\\f(6)=36-28\\f(6)=8

Finding f(4):

f(x)=x^2-3x-10\\f(4)=(4)^2-3(4)-10\\f(4)=16-12-10\\f(4)=16-22\\f(4)=-6

Now Putting values:

Rate\,\,of\,\,change=\frac{f(b)-f(a)}{b-a}

Rate\,\,of\,\,change=\frac{8-(-6)}{6-4}\\Rate\,\,of\,\,change=\frac{8+6}{2}\\Rate\,\,of\,\,change=\frac{14}{2}\\Rate\,\,of\,\,change=7

So, Rate of change is 7

Option B is correct.

Keywords: Rate of Change

Learn more about Rate of Change at:

  • brainly.com/question/3071107
  • brainly.com/question/6436086
  • brainly.com/question/2485860

#learnwithBrainly

8 0
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Factor this trinomial completely. 2x2 + 6x + 4 O
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Step-by-step explanation:

4 0
3 years ago
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The endpoints of the diameter of a circle are (−2, −3) and (4, −1). Which equation represents the circle?
Alika [10]

Answer:

The equation of circle is (x-1)^{2}+(y-2)^{2} = 18

Step-by-step explanation:

Given the endpoints of the diameter of a circle: (-2,-3) and (4,-1)

We know that the equation of circle is

(x-h)^{2} + (y-k)^{2}= r^{2}

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

(  \frac{x1+x2}{2} , \frac{y1+y2}{2}  )

( \frac{-2+4}{2} , \frac{-3-1}{2}  )

(1,2)

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Now substituting values of (h,k) and r^{2} in equation of circle, we get

(x-1)^{2}+(y-2)^{2} = 18

Hence the equation of circle is (x-1)^{2}+(y-2)^{2} = 18

5 0
3 years ago
Read 2 more answers
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