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3 years ago

Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. Assume free fall.

1 answer:

6 0

A) Vf = Vo - g*t
Vf = 0
g = 9.8 m/s^2

Vo = g* t => t up = Vo / g

t total = 2*t = 2*Vo / g

t slow = 2*Vo / g

t fast = 2*[3Vo] / g = 6Vo / g => Vo = g * t fast / 6 = 9.8 m/s^2 * 8.00 s / 6 = 13.07 m/s = Vo

t slow = 2 * 13.07 m/s / 9.8 m/s^2 = 2.67 s.

B)

Vf ^2 = Vo ^2 - 2gy

Vf = 0 => Vo ^2 = 2gy

Vo ^2 = 2gH

[3Vo]^2 = 2gy

=> [3Vo]^2 / Vo^2 = 2gy / 2gH
=> 9 = y/H => y = 9H

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The nutritional label above came from a can of soup how many servings of soup would you need to eat to receive your recommended

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Each serving gives 3 grams or 12% of daily recommended value. Divide 100% by 12% to get 8.33 servings to obtain the daily recommended value of 25 grams.

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3 years ago

What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol

san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

$Q=\frac{\Delta H}{n}$

where,

Q = energy absorbed = 27.2 kJ

$\Delta H$ = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

$27.2kJ=\frac{6.01kJ/mol}{n}$

$n=0.221mol$

Now we have to calculate the mass of ice.

$\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}$

Molar mass of ice = 18.02 g/mol

$\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g$

Thus, the mass of ice melted can be, 3.98 grams.

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4 years ago

What type of triangle measures 8 inches,8 inches,3 inches

kykrilka [37]

Answer:

isoceles

Explanation:

Because two sides are equal

7 0

3 years ago

Read 2 more answers

20. Consider a model steel bridge that is 1/100 the exact scale of the real bridge that is to be built. a. If the model bridge w

Veseljchak [2.6K]

The model bridge captures all the structural attributes of the real bridge, at a reduced scale.

Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.

Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.

Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.

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4 years ago

An object accelerates from rest and travels 53 m west in 5.2 s. Determine the acceleration

zmey [24]

Answer:

20.4m/s²

Explanation:

Given parameters:

Initial velocity = 0m/s

Distance = 53m

Time = 5.2s

Unknown:

Acceleration = ?

Solution:

This is a linear motion and we use the right motion equation;

S = ut + $\frac{1}{2}$ at²

S is the distance

u is the initial velocity

a is the acceleration

t is the time

Insert the parameters and solve;

53 = (0x 5.2) + $\frac{1}{2}$ x a x 5.2

53 = 2.6a

a = $\frac{53}{2.6}$ = 20.4m/s²

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3 years ago