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Angelina_Jolie [31]

3 years ago

14

A spring is 14cm long. Three masses are hung from it and then it is measured again. Now it is 19.5cm long. What force did the th

ree masses provide? The spring constant for the spring is 30N/m.

1 answer:

lukranit [14]3 years ago

3 0

Answer:

Gravity

Explanation:

The answer is gravity because when the 3 masses were hung from the spring, gravity pulled the spring towards the ground.

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Two charged spheres are 8.45 cm apart. They are moved, and the force on each of them is found to have been tripled. How far apar

Aleonysh [2.5K]

Force between two charges is given by

$F = \frac{kq_1q_2}{r^2}$

here force is inversely depends on the square of the distance

so here if distance is decreased the force will increase'

now if force is tripled

$\frac{3F}{F} = \frac{r^2}{r'^2}$

initially distance between charges was 8.45 cm

$3 = \frac{8.45^2}{r'^2}$

$r' = \frac{8.45}{\sqrt3}$

$r' = 4.88 cm$

so the distance between charges is 4.88 cm now

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What we see as "moonlight" is really reflected sunlight.<br><br> True or False?

uysha [10]

Yes, this is true. The only celestial body in the Milky Way universe that produces light is the Sun. It is the sole source of light for all the other planets and satellites. Our moon only 'borrows' light from the Sun. The surface of the moon acts as the mirror at which the Sun's light is reflected.

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A 1,790 W toaster, a 1,480 W electric frying pan, and a 60 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (Th

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Answer: ur mom

Explanation:

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3 years ago

A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di

solong [7]

Answer:

Before the plank will tip cat will walk 1.652 m

Explanation:

Mass of the cat along with plank $m_1=7kg$

Center of mass of the plank $d_1=0.850m$

Mass of cat $m_2=3.6kg$

We have to find how far right of sawhorse B.

Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.

Balancing the the torque

$m_1gd_1=m_1gd_2$

$7\times 9.8\times 0.850=3.6\times 9.8\times d_2$

$d_2=1.652m$

5 0

3 years ago

The membrane that surrounds a certain type of living cell has a surface area of 5.1 x 10-9 m2 and a thickness of 1.4 x 10-8 m.

ziro4ka [17]

a) The charge on the outer surface is $1.2\cdot 10^{-12} C$

b) The number of ions is $7.5\cdot 10^6$

Explanation:

a)

The membrane behaves as a parallel plate capacitor, whose capacity is given by the equation

$C=\frac{k\epsilon_0 A}{d}$

where

k = 4.3 is the dielectric constant

$\epsilon_0 =8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

$A=5.1\cdot 10^{-9} m^2$ is the surface area

$d=1.4\cdot 10^{-8} m$ is the distance between the two plates

Substituting,

$C=\frac{(4.3)(8.85\cdot 10^{-12})(5.1\cdot 10^{-9})}{1.4\cdot 10^{-8}}=1.4\cdot 10^{-11} F$

The capacity of the membrane is related to the potential difference between the two surfaces by

$C=\frac{Q}{\Delta V}$

where here we have

Q = excess charge on one surface

$\Delta V = 85.5 mV = 0.0855 V$ is the potential difference between the two surfaces

Solving for Q, we find

$Q=C\Delta V=(1.4\cdot 10^{-11})(0.0855)=1.2\cdot 10^{-12} C$

b)

We said that the net charge on the outer surface is

$Q=1.2\cdot 10^{-12} C$

The charge of one K+ ions is equal to the electron charge

$+e=1.6\cdot 10^{-19} C$

Therefore, the number of ions on the outer surface can be found by dividing the total charge by the charge of a single ion:

$N=\frac{Q}{e}=\frac{1.2\cdot 10^{-12}}{1.6\cdot 10^{-19}}=7.5\cdot 10^6$

Learn more about capacity:

brainly.com/question/10427437

brainly.com/question/8892837

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#LearnwithBrainly

6 0

3 years ago