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3 years ago

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Metal sphere A has a charge of -2 units and an identical sphere B has a charge of -4 units. If the spheres are brought into cont

act with each other and then separted the charge on sphere b will be

1 answer:

shusha [124]3 years ago

5 0

Answer:

q1 = q₂= -3

therefore each sphere has the same charge of -3 untis

Explanation:

The metallic spheres have mobile charge, so when the two spheres come into contact the total charge

Q_total = q₁ + q₂

Q_total = -2 -4

Q_total = -6 units

it is distributed in between the two spheres evenly since the charges of the same sign repel each other.

When the spheres separate each one has

q₁ = -6/2

q1 = q₂= -3

therefore each sphere has the same charge of -3 untis

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Two charges are in the configuration indicated here. The first charge, Q1 = –1.00 μC, sits at the origin. The second charge, Q2

blagie [28]

Answer:

$E_{net} = 3.6 \times 10^4 N/C$

Explanation:

As the two charges Q1 and Q2 are placed at some distance apart

so the electric field at mid point will be twice the electric field due to one charge

Because here the two charges are of opposite sign so here the electric field at mid point will be added due to both

so here we have

$E_{net} = 2E$

$E_{net} = 2(\frac{kQ}{r^2})$

distance of mid point from one charge is given as

$r = \frac{\sqrt{1^2 + 1^2}}{2}$

$E_{net} = 2 (\frac{(9\times 10^9)(1\times 10^{-6})}{(\frac{1}{\sqrt2})^2}$

$E_{net} = 3.6 \times 10^4 N/C$

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3 years ago

A strong-armed physics student throws a tennis ball vertically. The ball stays in the air for 5.5 seconds. Assuming the ball lef

Mila [183]

Answer:

27.5 m/s

Explanation:

applying motion equations we can find the answer,

v = u + a*t

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

t = time taken for the motion

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero (only a vertical speed component is there)

for the complete motion it takes 5.5 s. that means to reach the highest point it will take 5.5/2 =2.75 seconds

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g=10 m/s2)

that is,

v = 0 , a = -10 $ms^{-2}$ , t =2.75

v = u + at

0 = u -10*2.75

u = 27.5 $ms^{-1}$

4 0

4 years ago

A steel fork and a plastic spoon are both at the same temperature. The fork feels colder when you touch it. This is because:

Debora [2.8K]

Answer: The fork feels colder when you touch it because Steel conducts thermal energy better than plastic. The correct statement is 1

Explanation:

The ability of a material to transfer heat energy in an environment is known as thermal conductivity. It feels cooler to touch a steel spoon than a plastic spoon found in the same temperature because steel which is a type of metal is a highly efficient thermal conductor than spoon which is a plastic.

Metals can be defined as those substances which forms positive ion in a chemical reaction by lossing it's electrons. It has the following properties:

--> it is solid at room temperature

--> it has high melting point

--> it has high boiling point and

--> it is malleable.

Metals are said to be good thermal conductor because they contain free flowing conduction electrons. Therefore, when you touch a steel spoon and plastic spoon, it feels cooler because the steel metal is able to conduct heat away from your hand faster than the plastic which is a poor conductor of heat.

8 0

3 years ago

Read 2 more answers

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

a

$x_2 = -2.3356$

b

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

$v = u + at$

=> $v = 0.060 + (-0.380 * 3.80)$

=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

=> $x_2 = -2.3356$

6 0

3 years ago

A circuit consists of a 6 ohm resistor, a 0.2 farad capacitor, and an AC voltage source supplying V(t) = 120 cos(20 t) volts. Wr

Zinaida [17]

Answer:

q = 24 cos (20t) (1- e (-t / 1.2))

Explanation:

To work this circuit we use the mesh equation (Kirchoff) that states that the voltage in a closed circuit is zero

Vg + Vr + Vc = 0

Where Vg is the generator voltage, Vr the resistance voltage and Vc the capacitor voltage

Vg = 120 cos 20t = V

Vr = i R

Vc = q / C

We see that in one term we have the current (i) and in another the load (q), but there is a relationship between the two

i = dq / dt

Let's replace in the initial equation

V + R dq / dt + q / C = 0

Reorder the terms

Rdq / dt + q / C - V = 0

dq / dt + q / rC - V / R = 0

dq / dt = V / r -q / RC

dq / (V / R -q / RC) = dt

we integrate

∫I dq / (V / R - 1 / RC q) = ∫ dt

We change variables

u = (V / R - 1 / RC q)

du = -1 / RC dq

∫ dq / (V / R - 1 / RC q) = -RC ∫ du / u

-RC ln u = -RC ln (V / R - 1 / RC q)

We evaluate between the limits of integration, the lower t = 0 q (0) = 0

-RC [ln (V / R - 1 / RC q) - ln (V / R)] = t

[ln (V / R - 1 / RC q) - ln (V / R)] = -t / RC

Ln (V / R - 1 / RC q) / (V / R)] = -t / RC

Ln (1 - 1 / VC q)) = (-t / RC)

Ln (VC- q) = ln (VC) (-t / RC)

VC-q = VC e (-t / RC)

q = VC - Vc e (-t / RC)

q = VC (1- e (-t / RC)

We substitute the values they give us

q = (120 cos (20t) 0.2) (1- e (-t / 6 0.2))

q = 24 cos (20t) (1- e (-t / 1.2))

7 0

4 years ago