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3 years ago

13

Your tired 10 lb. baby cousin is cradled in your arms as you're walking back and forth across a 15m room to get her to fall asle

ep. Explain what work was done on the baby.

1 answer:

Mashcka [7]3 years ago

6 0

Work done = Force x Distance

Force = 10 lb = 44.5 N

Work Done = 44.5 N x 15 m

= 667.5 N-m

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Which phrases describe all the outer planets motion? Select two options

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Answer:

slow revolution and fast rotation

Explanation:

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3 years ago

Why is there zero current when a light bulb burns out?

kozerog [31]

The circuit is no longer closed.

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3 years ago

A transformer has 1000 turns in the primary coil and 100 turns in the secondary coil. If the primary coil is connected to a 120

alexdok [17]

Answer:

12 V, 0.5 A

Explanation:

For the Voltage,

Using,

Vs/Vp = Ns/Np.......................... Equation 1

Where Vs = Voltage in the secondary coil, Vp = Voltage in the primary coil, Ns = number of turn in the secondary coil, Np = number of turns in the primary coil.

Make Vs the subject of the equation

Vs = Vp(Ns/Np)........................ Equation 2

Given: Vp = 120 v, Np = 1000 turns, Ns = 100 turns

Substitute into equation 2

Vs = 120(100/1000)

Vs = 120×0.1

Vs = 12 v

For the current,

Using

Ns/Np = Ip/Is....................... Equation 3

Where Ip = current in the primary coil, Is = current in the secondary coil

make Is the subject of the equation

Is = Ip(Np/Ns).................. Equation 4

Given: Np = 1000 turns, Ns = 100 turns, Ip = 0.05 A

Substitute into equation 4

Is = 0.05(1000/100)

Is = 0.05×10

Is = 0.5 A.

Hence the voltage and the current in the secondary coil is 12 V, 0.5 A

4 0

3 years ago

Read 2 more answers

A 8.0-cm long solenoid has 2000 turns of wire and carries a current of 5.0-A. Calculate the strength of the magnetic field at th

CaHeK987 [17]

Answer:

B = 0.157 T

Explanation:

Given that,

Length of the solenoid, l = 8 cm = 0.08 m

Number of turns in the wire, N = 2000

Current, I = 5 A

We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :

$N=\mu_o nI$ , N is number of turns per unit length of solenoid.

So,

$B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T$

So, the magnetic field at the center of the solenoid is 0.157 T.

6 0

3 years ago

Two vectors are illustrated in the coordinate plane.

oksano4ka [1.4K]

Answer: (-4.3, 2.5)

Explanation:

In the second quadrant, magnitude of the vector is 5 and angle is 30° from the negative x-axis.

We can write this in terms of its components:

$-5 cos 30^o \hat i + 5 sin 30^o\hat j$

$-4.3\hat i+2.5 \hat j$

Thus, the components of vector in the second quadrant are (-4.3, 2.5)

4 0

3 years ago