The matter that has the same composition and properties throughout is called pure chemical substance. So the answer is substance.
Answer:
70.0 %
Explanation:
Step 1: Given data
- Mass of nitrogen (mN): 74.66 g
- Mass of the compound (mNxOy): 250 g
Step 2: Calculate the mass of oxygen (mO) in the compound
The mass of the compound is equal to the sum of the masses of the elements that form it.
mNxOy = mN + mO
mO = mNxOy - mN
mO = 250 g - 74.66 g = 175 g
Step 3: Determine the percent composition of oxygen in the sample
We will use the following expression.
%O = mO / mNxOy × 100%
%O = 175 g / 250 g × 100% = 70.0 %
Answer is the last one, it will not ionize, it already has an octet of electrons in it's valance shell
When there is a suffix outside a parenthesis, it multiplies every atom inside the parenthesis. so since in nitrogen is inside the parenthesis with a 2 as a suffix, it means there are 2 nitrogens
2 x 14.01= 28.02 g/mol
The value of k for this aqueous reaction at 298 k a b↽−−⇀c dδ°=10. 35 KJ/mol is 30.37 mol.
<h3>What is K? </h3>
K is the song which is used to donate the equilibrium of a reaction and the equilibrium of the reaction can only be obtained when the concentration of reactant is equal to the concentration of the product.
K is also known as the equilibrium constant.
δG or dδ° = - R T In K
R = universal gas constant
T = 298 k or 24.4Celciuss
dδ°= 10. 35
substituting the value in the equation
10. 35 = - 8.313 × 24.4 celcius In k
In k = - 8.313 × 24.4 celcius / 10. 35
In k = 30.37 mol.
Therefore, the value of k for this aqueous reaction at 298 k a b↽−−⇀c dδ°=10. 35 KJ/mol is 30.37 mol.
Learn more about K, here:
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