The balanced equation reaction :
2Cu+(aq) + PbO2(s) + SO42–(aq) + 4H+ -----------> PbSO4(s) + 2 Cu2+(aq) + 2H2O
A balanced equation is an equation for a chemical reaction in which the range of atoms for every detail in the reaction and the full charge is identical for both the reactants and the products. In other phrases, the mass and the fee are balanced in each aspect of the reaction.
A balanced equation happens while the variety of the atoms involved inside the reactants side is identical to the variety of atoms in the goods facet. in this chemical reaction, nitrogen (N2) reacts with hydrogen (H) to provide ammonia (NH3). The reactants are nitrogen and hydrogen, and the product is ammonia.
A chemical equation is the symbolic representation of a chemical reaction inside the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities.
Eo = Eored - Eo oxd
= 1.69 - 0.153
= 1.54 V
Eocell is positive so the reaction is spontaneous.
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Answer: 1.32
Explanation:
First, we must obtain the molar mass of HBr. After that, we try to obtain the concentration of the hydrobromic acid from the formula n=CV since the volume of solution and mass of acid was provided. Recall that n=m/M. If the concentration of acid is thus obtained, we make use of the fact that the concentration of H+ in the acid is equal to the molar concentration of HBr to obtain the pH. The pH is the negative logarithm of the concentration we obtained in the initial step.
Answer:
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
Explanation:
One colligative property is the freezing point depression due the addition of a solute. The equation is:
ΔT=Kf*m*i
<em>Where ΔT is change in temperature = 0.400°C</em>
<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>
<em>m is molality of the solution (Moles of solute / kg of solvent)</em>
<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>
Replacing:
0.400°C =1.86°C/m*m*1
0.400°C / 1.86°C/m*1 = 0.215m
As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:
0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.
The mass of ethylene glycol must be added is:
0.0602 moles * (62.10g / mol) =
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
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The arctic climate most likely
This is true there are many factors that influence the amount of a solute.
