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Alexxx [7]
3 years ago
11

Why do scientists use different types of models to represent compounds

Chemistry
2 answers:
denis23 [38]3 years ago
6 0

Answer is: scientists use different types of model to show different characteristics (chemical properties) of compound.

For example, ball and stick model gives informations about bond lenght and space filling model gives information about space occupied by atoms.

In chemistry, the ball-and-stick model is a molecular model of a chemical substance which is to display both the three-dimensional position of the atoms and the bonds between them.   The atoms are represented by spheres, connected by rods which represent the bonds. Every ball represent one atom in one molecule and they have different colors for different atoms (for example, carbon is black, hydrogen is white, nitrogen is blue).

There also other models: skeletal models, polyhedral models, composite models, computer-based models.


shutvik [7]3 years ago
5 0
Because they are different they all show different  traits
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3 years ago
How many moles of Sulfur (S) are equal to 1.806 x 10^24 atoms Sulfur?
mezya [45]

Answer:

b) 3.000 mol S

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using Avogadro's constant

1 mol = 6.02 × 10^23 atoms

we need to find the number of moles for 1.806 × 10^24

x = 1.806 × 10^24

putting it together we now have:

1 mol = 6.02 × 10^23 atoms

x = 1.806 × 10^24

cross multiply

6.02 × 10^23 x = 1.806 × 10^24

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3 0
2 years ago
1. What volume of gas (NU) is formed by the interaction of 13 g of zinc with 400 g of sulfuric acid solution with a mass fractio
Svetllana [295]

Answer:

4.5L of gas are produced

Explanation:

Based on the reaction:

Zn + H2SO4 → ZnSO4 + H2(g)

<em>Where 1 mole of Zn reacts with 1 mole of sulfuric acid to produce 1 mole of H2, the gas</em>

<em />

To solve this question we must find the moles of each reactant in order to find limiting reactant and, thus, the moles of H2 produced. Then using PV=nRT we can find the volume of the gas:

<em>Moles Zn -Molar mass: 65.38g/mol-</em>

13g * (1mol / 65.38g) = 0.20 moles Zn

<em>Moles H2SO4 -Molar mass: 98g/mol-</em>

400g * 10% = 40g H2SO4 * (1mol / 98g) = 0.41 moles H2SO4

As the ratio of the reaction is 1:1, the limiting reactant is Zn and the moles produced of H2 are 0.20 moles

Using PV = nRT; V = nRT/ P

<em>Where V is the volume of the gas </em>

<em>n are the moles = 0.20 moles</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K at STP</em>

<em>P is pressure = 1atm at STP</em>

<em />

V = 0.20mol*0.082atmL/molK*273.15K / 1atm

V = 4.5L of gas are produced

<em />

5 0
3 years ago
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