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Tatiana [17]
3 years ago
8

A chemist must dilute of aqueous potassium dichromate solution until the concentration falls to . He'll do this by adding distil

led water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Phantasy [73]3 years ago
5 0

The question is incomplete; the complete question is;

A chemist must dilute 99.4 mL of 152 mM aqueous potassium dichromate (K_2Cr_2O_7) solution until the concentration falls to 55.0 mM He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

0.275 L

Explanation:

From C1V1 = C2V2

Where;

C1= initial concentration of the solution 152 × 10^-3 M

V1= initial volume of the solution = 99.4 × 10^-3 L

C2 = concentration after dilution = 55 × 10^-3 M

V2 = volume after dilution = the unknown

V2 = C1 V1/C2

V2 = 152 × 10^-3 × 99.4 × 10^-3 / 55 × 10^-3

V2 = 0.275 L

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Answer:

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General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Aqueous Solutions</u>

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<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

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<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 24.9235 \ L \ Ar

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

24.9235 L Ar ≈ 24.9 L Ar

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