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3 years ago

What is the quotient of the following division problem?

Mathematics

2 answers:

LekaFEV [45]3 years ago

6 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Step-by-step explanation:

We need to find quotient of x^2+3x+2 divided by x+1

The division is shown in figure attached.

Quotient: x+2

Remainder: 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Mekhanik [1.2K]3 years ago

5 0

Answer:

x+2

Step-by-step explanation:

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x = 20 × 0.573

x = 11.46

x = 11.5

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Step-by-step explanation:

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3 years ago

Mr green makes some compost he mixes soil, manure and leaf mould in the ratio 3:1:2 mr greenmakes 72 literes of the compost. How

love history [14]

Answer:

$36\ liters\ of\ soil$

Step-by-step explanation:

we know that

The ratio of soil, manure and leaf mould is $3:1:2$

That means

For every 6 liters of the compost, he use 3 liters of soil

so by proportion

Find how many liters of soil does he use for 72 liters of compost

$\frac{3}{6}=\frac{x}{72}\\ \\x=3*72/6\\ \\x=36\ liters\ of\ soil$

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3 years ago

What is a capacity of 25 fl oz more than a capacity of 3 cups

nata0808 [166]

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3 years ago

A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.

dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0

3 years ago