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kirza4 [7]
3 years ago
9

What is the quotient of the following division problem?

Mathematics
2 answers:
LekaFEV [45]3 years ago
6 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Step-by-step explanation:

We need to find quotient of x^2+3x+2 divided by x+1

The division is shown in figure attached.

Quotient: x+2

Remainder: 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Mekhanik [1.2K]3 years ago
5 0

Answer:

x+2

Step-by-step explanation:

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Helppp will brainlist 20 points :((((
makvit [3.9K]

Answer:

30 I am pretty sure

Step-by-step explanation:

5 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
3 years ago
Mary and Roberto go to the movies. They buy a large popcorn for $8.50, and two medium sodas for $4.25. How much did they spend a
alukav5142 [94]

Answer:

$19.15

Step-by-step explanation:

Equation 1: 8.50+4.25+4.25= 17.00  (price of the popcorn and drinks)

Equation 2: 17.00/7.89= 2.15                       (how to find how much the tax is)

Solve: 17.00+2.15=19.15                     (add the tax to how much the popcorn and drinks were)

6 0
3 years ago
Solve this exercise using the fact that the sum of the measures of the three angles of a triangle is 180.
den301095 [7]

Answer:

X=70

Step-by-step explanation:

70 + 75 + 35 =180

x + x+5 + x-35

7 0
3 years ago
Use the stem and leaf plot shown to answer the following question.
DENIUS [597]
16, 18, 23, 25, 26, 34, 37, 37, 40, 41, 46

37 is the upper quartile value
6 0
3 years ago
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