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kirza4 [7]
4 years ago
9

What is the quotient of the following division problem?

Mathematics
2 answers:
LekaFEV [45]4 years ago
6 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Step-by-step explanation:

We need to find quotient of x^2+3x+2 divided by x+1

The division is shown in figure attached.

Quotient: x+2

Remainder: 0

The quotient of x + 1 StartLongDivisionSymbol x squared + 3 x + 2 EndLongDivisionSymbol is x+2

Mekhanik [1.2K]4 years ago
5 0

Answer:

x+2

Step-by-step explanation:

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Create an example of a situation where there is a negative cash flow.
dimaraw [331]

Answer:

when say your expenses are $400 a month but your income is only $350 a month that is -$50 every month so in that case you aren't getting a positive cash flow (which would be making more money than your expenses) So you must be getting a negative cash flow in which you are losing money and going into debt.

Hope this Helps :)

6 0
3 years ago
Z^m-n (z^m+ z^m+n + z^n)
rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

8 0
3 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
Which of the following ordered triples is the solution to the system of equations?
Sever21 [200]

A. all of the answers are correct when you plug in these values

4 0
3 years ago
Evaluate 3x+4 for the given values of x
galina1969 [7]

Answer:

b) 3(9) + 4 = 36 + 4 = 40

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d) 3(-3) + 4 = -9 + 4 = -5

e) 3(8) + 4 = 24 + 4 = 28

6 0
3 years ago
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