(a) The voltage that is produced in the secondary circuit is 1,800 V.
(b) The current that flows in the secondary circuit is 1 A.
<h3>Voltage in the secondary coil</h3>
Np/Ns = Vp/Vs
where;
- Np is number of turns in primary coil
- Ns is number of turns in secondary coil
- Vp is voltage in primary coil
- Vs is voltage in secondary coil
100/1500 = 120/Vs
Vs = (120 x 1500)/100
Vs = 1,800 V
<h3>Current in the secondary coil</h3>
Is/Ip = Vp/Vs
where;
- Is is secondary current
- Ip is primary current
Is = (IpVp)/Vs
Is = (15 x 120)/1800
Is = 1 A
Thus, the voltage that is produced in the secondary circuit is 1,800 V.
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