Answer:
![9.45179\ m/s^2](https://tex.z-dn.net/?f=9.45179%5C%20m%2Fs%5E2)
![s=4.725895t^2](https://tex.z-dn.net/?f=s%3D4.725895t%5E2)
Explanation:
t = Time taken = 0.46
u = Initial velocity
v = Final velocity
s = Displacement = 1 m
a = Acceleration
![s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%201%3D0%5Ctimes%200.46%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%200.46%5E2%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B1%5Ctimes%202%7D%7B0.46%5E2%7D%5C%5C%5CRightarrow%20a%3D9.45179%5C%20m%2Fs%5E2)
The acceleration due to gravity is 9.45179 m/s²
![s=ut+\frac{1}{2}at^2\\\Rightarrow s=\frac{1}{2}at^2\\\Rightarrow s=\dfrac{1}{2}9.45179t^2\\\Rightarrow s=4.725895t^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7B1%7D%7B2%7D9.45179t%5E2%5C%5C%5CRightarrow%20s%3D4.725895t%5E2)
The function is ![s=4.725895t^2](https://tex.z-dn.net/?f=s%3D4.725895t%5E2)
Answer:
7 orbitals are allowed in a sub shell if the angular momentum quantum number for electrons in that sub shell is 3.
Explanation:
We that different values of m for a given l provide the total number of ways in which a given s, p,d and f sub shells in presence of magnetic field can be arranged in space along x, y ,z- axis or total number of orbitals into which a given subshell can be divided.
Range for given l lies between -l to +l .
The possible values of m are -3 , -2 , -1 , 0 , 1 ,2 , 3 .
Total number of orbitals are 7.
Answer:
Please, in the Explanation section you will find the explanation of the answer.
Explanation:
The exercise shows the continental United States and 3 cities used in the study carried out by Murdock. It can be said that the sample taken is part of the objective. There are several inconsistencies in Murdock's argument: the first has to do with the fact that the sample that was taken cannot represent the entire American population. A much larger, scientifically calculated sample would be required. The second is that their study did not take into account small cities or people living in the interior of the United States.
Answer:
Current = 8696 A
Fraction of power lost =
= 0.151
Explanation:
Electric power is given by
![P=IV](https://tex.z-dn.net/?f=P%3DIV)
where I is the current and V is the voltage.
![I=\dfrac{P}{V}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BP%7D%7BV%7D)
Using values from the question,
![I=\dfrac{1000\times10^6 \text{ W}}{115\times10^3\text{ V}} = 8696 \text{ A}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B1000%5Ctimes10%5E6%20%5Ctext%7B%20W%7D%7D%7B115%5Ctimes10%5E3%5Ctext%7B%20V%7D%7D%20%3D%208696%20%5Ctext%7B%20A%7D)
The power loss is given by
![P_\text{loss} = I^2R](https://tex.z-dn.net/?f=P_%5Ctext%7Bloss%7D%20%3D%20I%5E2R)
where R is the resistance of the wire. From the question, the wire has a resistance of
per km. Since resistance is proportional to length, the resistance of the wire is
![R = 0.050\times40 = 2\Omega](https://tex.z-dn.net/?f=R%20%3D%200.050%5Ctimes40%20%3D%202%5COmega)
Hence,
![P_\text{loss} = \left(\dfrac{200000}{23}\right)^2\times2](https://tex.z-dn.net/?f=P_%5Ctext%7Bloss%7D%20%3D%20%5Cleft%28%5Cdfrac%7B200000%7D%7B23%7D%5Cright%29%5E2%5Ctimes2)
The fraction lost = ![\dfrac{P_\text{loss}}{P}=\left(\dfrac{200000}{23}\right)^2\times2\div (1000\times10^6)=\dfrac{80}{529}=0.151](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%5Ctext%7Bloss%7D%7D%7BP%7D%3D%5Cleft%28%5Cdfrac%7B200000%7D%7B23%7D%5Cright%29%5E2%5Ctimes2%5Cdiv%20%281000%5Ctimes10%5E6%29%3D%5Cdfrac%7B80%7D%7B529%7D%3D0.151)