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Pepsi [2]
3 years ago
15

When we plot all the points that satisfy an equation or inequality we ___ it.

Physics
2 answers:
snow_tiger [21]3 years ago
6 0
We<span> use </span>inequalities<span> when there is a range of possible answers for a situation. ... </span>inequalities—inequalities<span> that can be written in the form of a linear </span>equation. ... the bounded region, and anypoint<span> within this region </span>satisfies<span> the </span>inequality<span> x ≥ -</span><span>2. ... </span>All<span> of the </span>points<span> under the line are shaded; this is the range of </span>points<span> where the ...</span>
Sergio039 [100]3 years ago
5 0

I just took this test!

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Two charges q1 and q2, that are distance d apart , repel each other with a force of 6.40 N. what would be the force between two
slava [35]

Q: Two charges q1 and q2, that are distance d apart , repel each other with a force of 6.40 N. what would be the force between two charges q1'=2q1 and q2'=3q2 that that are distance d apart?

Answer:

The force = 38.4 N

Explanation:

From coulombs law,

F = kq₁q₂/r² ............................ Equation 1

Where F = Force of attraction or repulsion between the charges, q₁ and q₂ = first and second charge respectively, r = distance between the charges, k = constant of proportionality.

When, F = 6.4 N, r = d m.

6.4 = kq₁q₂/d²......................... Equation 1

When q₁' = 2q₁, q₂' = 3q₂, r = d cm

F = k(2q₁)(3q₂)/d²

F = 6kq₁q₂/d².......................... Equation 2

Dividing Equation 1 by equation 2

6.4/F = kq₁q₂/d²/(6kq₁q₂/d²)

6.4/F = 1/6

F = 6.4×6

F = 38.4 N.

Thus the force = 38.4 N

6 0
4 years ago
the force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity
PIT_PIT [208]

The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.

Weight is the force of gravity acting on a body.

The formula is :

                                W =mg

Here,

W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.

Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.

If you need to learn about the difference between mass and weight, click here

brainly.com/question/23876249?referrer=searchResults

#SPJ4

8 0
1 year ago
A 200-foot tall monument is located in the distance. From a window in a building, a person determines that the angle of elevatio
egoroff_w [7]

Answer:

665 ft

Explanation:

Let d be the distance from the person to the monument. Note that d is perpendicular to the monument and would make 2 triangles with the monuments, 1 up and 1 down.

The side length of the up right-triangle knowing the other side is d and the angle of elevation is 13 degrees is

dtan13^0 = 0.231d

Similarly, the side length of the down right-triangle knowing the other side is d and the angle of depression is 4 degrees

dtan4^0 = 0.07d

Since the 2 sides length above make up the 200 foot monument, their total length is

0.231d + 0.07d = 200

0.301 d = 200

d = 200 / 0.301 = 665 ft

7 0
3 years ago
2) A car is towed by a horizontal rope at a constant speed.<br> draw the free body diagram
Temka [501]

Answer:

\

\

\

Explanation:

8 0
3 years ago
Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha
Ivan

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a   it is always zero

b  0

c  \eta  =  -\epsilon _o E

Explanation:ss

Here the  net charge is  on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area  which implies that the charge density is dependent on the net charge  so this  means that the charge density inside the conductor is zero

 

Generally the direction of electric field this from the  positive charge to the negative charge  so from the question we can deduce  that the negative charge is located on the surface of the conductor

    So We can mathematically define the charge density on the surface of the electric field as

             ∮E \cdot dA =  \frac{-Q}{\epsilon _o}

Where E is the electric field

          dA change in unit area

           -Q is the negative charge

          \epsilon _o  is the permittivity of free space

So

          EA  =  \frac{-Q}{\epsilon _o }

           \frac{Q}{A}  =  -\epsilon _o E

          \eta  =  -\epsilon _o E

Where \eta is the charge density

   

8 0
3 years ago
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