Ask question

Ask question

All categories

3 years ago

15

When we plot all the points that satisfy an equation or inequality we ___ it.

2 answers:

snow_tiger [21]3 years ago

6 0

We<span> use </span>inequalities<span> when there is a range of possible answers for a situation. ... </span>inequalities—inequalities<span> that can be written in the form of a linear </span>equation. ... the bounded region, and anypoint<span> within this region </span>satisfies<span> the </span>inequality<span> x ≥ -</span><span>2. ... </span>All<span> of the </span>points<span> under the line are shaded; this is the range of </span>points<span> where the ...</span>

Sergio039 [100]3 years ago

5 0

I just took this test!

You might be interested in

Systems distribute heat energy by the circulation of air.

Ulleksa [173]

That seems like a statement more than a question. Where's the question?

6 0

3 years ago

Read 2 more answers

If the mean velocity adjacent to the top of a wing of 1.8 m chord is 40 m/s and that adjacent to the bottom of the wing is 31 m/

Cloud [144]

Answer:

lift per meter of span = 702 N/m

Explanation:

See attached pictures.

7 0

3 years ago

A fan blade, initially at rest, rotates with a constant acceleration of 0.029 rad/s2. What is the time interval required for it

LenKa [72]

Answer:

The time interval is $t = 21.30 \ s$

Explanation:

From the question we are told that

The constant acceleration is $\alpha = 0.029 \ rad / s^2$

The displacement is $\theta = 6.58 \ rad$

According to the second equation of motion we have that

$\theta = w_i* t + \frac{1}{2} * \alpha t^2$

given that the blade started from rest

$w_i$ which is the initial angular velocity is 0

So

$\theta = 0 + \frac{1}{2} * \alpha t^2$

=> $t = \sqrt{ \frac{2 * \theta }{\alpha } }$

substituting values

=> $t = \sqrt{ \frac{2 * 6.58 }{0.029 } }$

=> $t = 21.30 \ s$

6 0

3 years ago

PLEASE HELP ME WITH MY QUIZ!!!!

egoroff_w [7]

Answer:

The answer is b the radiation of the suns electromagnetic waves

Explanation:

I took the Quiz to.

6 0

3 years ago

A bus starts from rest and accelerates to 14 m/s in 4 s. What is the

Komok [63]

Acceleration = 14/4 = ....

3 0

3 years ago