All categories

2 years ago

How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?

Physics

1 answer:

ICE Princess25 [194]2 years ago

5 0

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

$W = P\Delta V$

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

$W = P(0\ m^3)\\$

You might be interested in

hot-air balloon is ascending at the rate of 14 m/s and is 84 m above the ground when a package is dropped over the side. (a) How

timurjin [86]

Answer:

a) t = 4.14 s

b) Speed with which it hits the ground = 40.58 m/s

Explanation:

Using the equations of motion,

g = 9.8 m/s², y = H = 84 m,

Initial velocity, u = 0 m/s,

final velocity, v = ?

Total Time of fall, t = ?

a) y = ut + gt²/2

84 = 0 + 9.8t²/2

4.9t² = 84

t² = 84/4.9

t = 4.14 s

b) v = u + gt

v = 0 + (9.8 × 4.14)

v = 40.58 m/s

4 0

3 years ago

Read 2 more answers

Describe three clues that tell you that you are o serving a chemical change. Give an Example of each clues you described.

sergiy2304 [10]

1) the object would change color (start to rust or just chnage color)

2) The new substance is ireversable (cant chnage back to original form)

3)theres gas formations (its can change into a gas property)

3 0

3 years ago

135g of an unknown substance gains 9133 J of heat as it is heated from 25⁰C to 100⁰C. Using the chart below, determine the ident

telo118 [61]

Answer:

The unknown substance is Aluminum.

Explanation:

We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:

Initial temperature (T₁) = 25 ⁰C

Final temperature (T₂) = 100 ⁰C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 25

ΔT = 75 ⁰C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Change in temperature (ΔT) = 75 ⁰C

Mass of the substance (M) = 135 g

Heat (Q) gained = 9133 J

Specific heat capacity (C) of substance =?

Q = MCΔT

9133 = 135 × C × 75

9133 = 10125 × C

Divide both side by 10125

C = 9133 / 10125

C = 0.902 J/gºC

Thus, the specific heat capacity of substance is 0.902 J/gºC

Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.

7 0

2 years ago

1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground

Svetradugi [14.3K]

You have three known variables:

Acceleration - $9.8m/s^2$
Time - $1.85s$
Initial Velocity - $0m/s$

For the first part of your question:

$v = u + at

v = (0)+(9.8)(1.1)

v = 10.78 m/s v=11 m/s (2 significant figures)$

For the second part of your question:

$v=u+at

v=(0)+(9.8)(1.85)
v=18.13 m/s

$

This still needs to be converted to m/h:

$18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour

65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h

= 41 mi/hr (2 significant figures)
$

5 0

3 years ago

Read 2 more answers

A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and th

fgiga [73]

What class is this for?

3 0

3 years ago