Light incident on a surface at an angle of 45° undergoes diffused reflection at what angle will it reflect?
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Answer:
Explanation:
let the ball is thrown vertically downwards with velocity u.
So, initial velocity, = - u (downwards)
acceleration = - g (downwards)
let the velocity is v after time t.
use first equation of motion
v = u + at
- v = - u - gt
v = u + gt
So, it is a straight line having slope g and y intersept is u.
The graph I shows the velocity - time graph.
Now the value of acceleration remains constant and it is equal to - 9.8 m/s^2.
So, acceleration time graph is a starigh line parallel to time axis having slope zero.
the graph II shows the acceleration - time graph.
Use III equation of motion to find the final speed in terms height.
And the time is
v = u + gt
