Answer:
7.6 g
Explanation:
"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.
The heat gained by the copper, water, and ice = the heat lost by the steam
Heat gained by the copper:
q = mCΔT
q = (120 g) (0.40 J/g/K) (40°C − 0°C)
q = 1920 J
Heat gained by the water:
q = mCΔT
q = (70 g) (4.2 J/g/K) (40°C − 0°C)
q = 11760 J
Heat gained by the ice:
q = mL + mCΔT
q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)
q = 4880 J
Heat lost by the steam:
q = mL + mCΔT
q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)
q = 2452 J/g m
Plugging the values into the equation:
1920 J + 11760 J + 4880 J = 2452 J/g m
18560 J = 2452 J/g m
m = 7.6 g
Answer:
E = 440816.32 N/C
Explanation:
Given data:
Three point charge of charge equal to +3.0 micro coulomb
fourth point charge = - 3.0 micro coulomb
side of square = 0.50 m
N.m^2/c^2
Due to having equal charge on center of square, 2 charge produce equal electric field at center and other two also produce electric field at center of same value
So we have
[
[
]
plugging all value
E = 440816.32 N/C
Answer:
if your glasses are polarized, you can see the fish in the water. also im pretty sure its d
Explanation:
