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k0ka [10]
3 years ago
12

Light incident on a surface at an angle of 45° undergoes diffused reflection at what angle will it reflect?

Physics
1 answer:
Evgen [1.6K]3 years ago
5 0

Answer:

Option (D)

Explanation:

Reflection is the phenomenon in which a ray of light strikes on a smooth and polished surface and then bounce back into the same medium at same angle.

There are two types of reflection.

1. Regular reflection or specular reflection

2. Irregular reflection or diffused reflection

When a parallel beam of light falls on a smooth and highly polished surface and after reflection the rays are also parallel to each other, it is called regular reflection.

When after parallel beam of light falls on a rough surface and after reflection the rays of light goes in random directions, it is called diffused reflection.

The rays reflected at 90 degree to - 90 degree in diffused refectory.

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How many times a minute does your heart usually beat?
ycow [4]

Answer:

60-100

Explanation:

A normal resting heart rate for adults ranges from 60 to 100 beats per minute. Generally, a lower heart rate at rest implies more efficient heart function and better cardiovascular fitness.

HOPE THIS HELPS!!! HAVE A GREAT DAY!!!

7 0
3 years ago
Read 2 more answers
On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnet
Otrada [13]

Answer:

1.907 x 10⁻⁵ J.

Explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

E = \mu V

E = (\dfrac{S}{c})\times V

where c is the speed of light.

E = (\dfrac{1.1\times 10^3}{3\times 10^8})\times 5.20

E = 1.907\times 10^{-5}\ J

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.

4 0
4 years ago
Calculate potential energy
IrinaVladis [17]
The potential energy of an object is defined by the equation: PE = mgh, where m = the mass of the object, g = the gravitational acceleration and h = the object's height above the ground.
4 0
4 years ago
A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet
Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

K.E = 1/2 × m × v2

Where m is mass

v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

g is acceleration of free fall due to gravity = 9.8m/S2

h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

From the foregoing analysis of energy conversation it implies;

1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

=>1/2 × (187.5)^2 / 9.8 = h

=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

3 0
3 years ago
A series circuit has two 10-ohm bulb is added in a series. Technician A says that the three bulbs will be dimmer than when only
ANTONII [103]

Answer:

Technician  A  is right. The situation will happens even with only two bulbs in series

Explanation:

We must take into account that

1.- All electric device need its nominal voltage to operate

2.-Any and all electric device means an electric load for the source in terms of equation that means any device will implies a drop voltage of V = I*R ( I the flows current and R  the resistance of the device)

3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).

4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split  between the two bulbs ( we  could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.

For that reason all the bulbs are connected in parallel in wich case all of them will operate with the common voltage

4 0
3 years ago
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