You could use grams hope this helps
Complete question is;. A 73mH solenoid inductor is wound on a form that is 0.80m long and 0.10m in diameter a coil having a resistance of 7.7 ohms is tightly wound around the solenoid at its center the mutual inductance of the coil and solenoid is 19μH at a given instant the current in the solenoid is 820mA and is decreasing at the rate of 2.5A/s at the given instant what is the induced current in the coil
Answer:
6.169 μA
Explanation:
Formula for induced EMF is given by the equation;
EMF = M(di/dt). We are given;
di/dt = 2.5 A/s
M = 19μH = 19 × 10^(-6) H
Thus;
EMF = 19 × 10^(-6) × 2.5.
EMF = 47.5 × 10^(-6) V
Formula for current is;
i = EMF/R. R is resistance given as 7.7 ohms.
Thus; i = 47.5 × 10^(-6)/7.7
i = 6.169 μA
<span>Nuclear power plants produce radioactive
waste that must be stored properly. It is very impossible for a nuclear power plant
to have no waste at all since lots of chemicals are used to create the process
as it gives energy to other machines. Nuclear energy can be used to power all
of the above choices. Radioactive waste can not be released into local water
supplies since the wastes are very radioactive and may cause mutation to the
fishes and bioaccumulation which will affect humans as well. It will also cause
air pollution if the chemicals are not stored properly.</span>
Well if it was traveling for an hour then the answer is 8 miles.
